用Identity_Insert插入数据是ON并插入到Table1中从表2中选择*

Question

CREATE TABLE TestTable (id int IDENTITY (1,1), name nvarchar(100)); 
INSERT INTO TestTable(name) VALUES ('data1');      
INSERT INTO TestTable(name) VALUES ('data2');      
Declare @Identity as int 
set @identity=IDENT_CURRENT ('TestTable') 
SET IDENTITY_INSERT TestTable ON; 

我如何实现此功能？

INSERT INTO TestTable 
Select * from 
(
Select 55 as a,'data55' as b 
Union 
Select 56 as a,'data55' as b 
)n 

当这种被替换然后.. 消息8101，级别16，状态1，行7 当使用列列表只能指定表“TestTable的”标识列的显式值和IDENTITY_INSERT已打开。

INSERT INTO TestTable (id, name) VALUES (55, 'data55');  
INSERT INTO TestTable (id, name) VALUES (56, 'data55');  

SET IDENTITY_INSERT TestTable OFF; 
DBCC CHECKIDENT (TestTable, reseed,@identity) 
INSERT INTO TestTable(name) VALUES ('data3');     
Select * from TestTable 
Drop table TestTable 

Answer 1

你需要说

INSERT INTO TestTable (id, name) 
Select * from 
( 
Select 55 as a,'data55' as b 
Union 
Select 56 as a,'data55' as b 
)n 

Answer 2

这应该正常工作：

SET IDENTITY_INSERT TestTable ON; 

INSERT INTO TestTable(id, name) 
Select * 
from 
( 
    Select 55 as a, 'data55' as b 
    Union 
    Select 56 as a, 'data55' as b 
)n; 

刚刚成立SET IDENTITY_INSERT ON与INSERT子句中列出的字段。