如何找到确切的年，天

表如何找到确切的年，天

id date-of-birth 

001 01/01/2011 'dd/mm/yyyy' 
002 05/01/2012 
003 15/05/2009 
....

从上面的表格，我想从计算天数日期的联接列，日期的出生应该从当年验证。

查找的时间差查询

Select id, DATEDIFF(dd,Convert(datetime, date-of-join, 103),getdate())

上面的查询从日期的联接工作，但二要验证的日期的，加入这样的...

例如

id date-of-birth no-of-days 

001 01/01/2011 64 
002 05/01/2012 60 
003 15/05/2009 295

....

条件

For 001, date-of-birth is '01/01/2011', so one year exceeded, then it should give no-0f-days from '01/01/2012' 

For 002, date-of-birth is '05/01/2012, so it is not exceeded one years, then it should give no-of-days from '05/01/2012' 

For 003, date-of-birth is '15/05/2009', so it is exceeded more than a years, then it should calculate from 15/05/2011 to current date

任何一个可以提供一些思路或查询帮助

来源

2012-03-05 JetJack

尝试：

select id, 
     [date-of-birth], 
     datediff(yy,[date-of-birth],getdate()) - 
        case when dateadd(yy,datediff(yy,[date-of-birth],getdate()),[date-of-birth])>getdate() 
        then 1 else 0 end as [no-of-years], 
     datediff(d, 
       dateadd(yy,datediff(yy,[date-of-birth],getdate()) - 
          case when dateadd(yy,datediff(yy,[date-of-birth],getdate()),[date-of-birth])>getdate() 
          then 1 else 0 end,[date-of-birth]), 
       getdate()) as [no-of-days] 
from ...

来源

2012-03-05 14:09:05

declare @T table (id int identity(100,1), date datetime) 
insert @T values('2012-05-01') 
insert @T values('2012-03-1') 
insert @T values('2011-01-01') 
insert @T values('2009-05-15') 
insert @T values('2008-01-23') 

select 
    id, 
    date, 
    Days = case when datediff(dd,date,getdate())>730 
        then datediff(dd,date,getdate()) - (datediff(dd,date,getdate())/365 * 365) 
       when datediff(dd,date,getdate())>365 
        then datediff(dd,convert(datetime, datename(yy,getdate()) + '/01/01'),getdate()) 
       else abs(datediff(dd,date,getdate())) 
      end 
from @T

来源

2012-03-05 21:37:27 jim31415

如何找到确切的年，天

回答

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