我队 S的编码器小号项目 S的任务 S的。如何根据儿童孩子的人数排序EF父母?
如何有效地排序队 01用任务 S IN实体框架的使用方法的语法和代码优先的方法号(可能没有加载儿童儿童的整个集合内容,我需要那种只)?
public class MyAppContext : DbContext
{
public DbSet<CTeam> Teams { get; set; }
// ...etc
}
[Table("Team")]
public class CTeam
{
public int ID { get; set; }
[MaxLength(128)]
public string Title { get; set; }
[Display(Name = "Coders")]
public virtual ICollection<CCoder> Coders { get; set; }
}
[Table("Coder")]
public class CCoder
{
public int ID { get; set; }
[MaxLength(128)]
public string Name { get; set; }
public virtual ICollection<CProject> Projects { get; set; }
public int TeamID { get; set; }
public virtual CTeam Team { get; set; }
}
// CProject and CTask similarly
或者,如果你可以给一个暗示原始的SQL应该怎么看起来像这个,这将有助于太。谢谢!
UPDATE
与关系Builder -> NewBuildingObject -> NewBuildingHouse -> NewBuildingLayout
对于观众的舒适,特奥多尔·伊万诺夫的回答一个项目:
context.Teams
.OrderBy(x => x.Coders
.SelectMany(y => y.Projects)
.SelectMany(y => y.Tasks)
.Count());
做出EF生成验证码:
SELECT
[Project1].[ID] AS [ID],
[Project1].[Title] AS [Title]
FROM (SELECT
[Extent1].[ID] AS [ID],
[Extent1].[Title] AS [Title],
(SELECT
COUNT(1) AS [A1]
FROM [dbo].[NewBuildingObject] AS [Extent2]
INNER JOIN [dbo].[NewBuildingHouse] AS [Extent3] ON [Extent2].[ID] = [Extent3].[ObjectID]
INNER JOIN [dbo].[NewBuildingLayout] AS [Extent4] ON [Extent3].[ID] = [Extent4].[HouseID]
WHERE [Extent1].[ID] = [Extent2].[BuilderID]) AS [C1]
FROM [dbo].[Builder] AS [Extent1]
) AS [Project1]
ORDER BY [Project1].[C1] ASC
和雅各布·马萨德的回答是:
var teams = context.Teams
.OrderBy(team =>
team.Coders.SelectMany(coder =>
coder.Projects.SelectMany(project => project.Tasks)).Count());
使这个代码:
SELECT
[Project1].[ID] AS [ID],
[Project1].[Title] AS [Title]
FROM (SELECT
[Extent1].[ID] AS [ID],
[Extent1].[Title] AS [Title],
(SELECT
COUNT(1) AS [A1]
FROM [dbo].[NewBuildingObject] AS [Extent2]
INNER JOIN (SELECT [Extent3].[ObjectID] AS [ObjectID]
FROM [dbo].[NewBuildingHouse] AS [Extent3]
INNER JOIN [dbo].[NewBuildingLayout] AS [Extent4] ON [Extent3].[ID] = [Extent4].[HouseID]) AS [Join1] ON [Extent2].[ID] = [Join1].[ObjectID]
WHERE [Extent1].[ID] = [Extent2].[BuilderID]) AS [C1]
FROM [dbo].[Builder] AS [Extent1]
) AS [Project1]
ORDER BY [Project1].[C1] ASC
谢谢!您的解决方案运行良好。我最早接受这个答案。 – Roman