2017-12-03 160 views
1

我有一个函数可以返回每天的销售计数。这种方法的问题是,我希望将数据按日期存储,但我让他们按以下顺序:按日期排序的退货数据

01-Dec 
02-Dec 
03-Dec 
03-Nov 
04-Nov 
05-Nov 
etc. 

我明白为什么出现这种情况,但我不知道如何解决它。我可以用startofmonth代替subMonth(1),这会部分解决我的问题,但这不是我想要的。我反而希望返回订购的最后30天。

return DB::table('sales') 
     ->select(\DB::RAW('DATE_FORMAT(created_at, "%d-%M") as date'), \DB::raw('COUNT(*) as count')) 
     ->where('created_at', '>=', Carbon::now()->subMonth(1)) 
     ->orderBy('date') 
     ->groupBy('date') 
     ->get(['date', 'count']) 
     ->keyBy('date') 
     ->transform(function ($data) { 
      return $data->count; 
     }); 

我也试过orderBy('created_at'),但它给了我下面的错误,我想避免更改sql模式。

Syntax error or access violation: 1055 Expression #3 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'x.sales.created_at' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by 

编辑: 按照要求,该return语句

select DATE_FORMAT(created_at, "%d-%M") as date, COUNT(*) as count from `sales` where `created_at` >= ? group by `date` order by `date` asc 
+0

请张贴生成的SQL – lad2025

+0

@ lad2025我只是没:) – George

+0

请尝试:' - > GROUPBY( '1')'代替' - > GROUPBY( '日')' – lad2025

回答

0

的SQL查询我没有你的框架查询语法太多的想法。但是您可以在显示数据时再添加一列DATE_FORMAT(created_at,“%Y%m%d”)作为order_column并应用顺序,并按列“order_column”分组,并使用列“data”。

select DATE_FORMAT(created_at, "%Y%m%d") AS order_column, DATE_FORMAT(created_at, "%d-%M") as date, COUNT(*) as count from `sales` where `created_at` >= ? group by `order_column` order by `order_column` asc 



return DB::table('sales') 
     ->select(\DB::RAW('DATE_FORMAT(created_at, "%Y%m%d") AS order_column'),\DB::RAW('DATE_FORMAT(created_at, "%d-%M") as date'), \DB::raw('COUNT(*) as count')) 
     ->where('created_at', '>=', Carbon::now()->subMonth(1)) 
     ->orderBy('order_column') 
     ->groupBy('order_column') 
     ->get(['date', 'count']) 
     ->keyBy('date') 
     ->transform(function ($data) { 
      return $data->count; 
     }); 
+0

Yeap,这与获取原始'created_at'值相同。我可以按原始的created_at排序,但是我得到了上面提到的错误(sql_mode = only_full_group_by)和两种情况。我想我将不得不改变mysql设置来完成这个... – George

0

如果你在2个步骤中做到这一点,它是否工作?

第一步,在其中创建日期列:

$step1 = DB::table('sales') ->select(\DB::RAW('DATE_FORMAT(created_at, "%d-%M") as date'))) 
->where('created_at', '>=', Carbon::now()->subMonth(1)) 
->orderBy('date') 
->get(['date', 'count']) 

之后,你做agregation:

$step2 = $step1->select('date'), \DB::raw('COUNT(date) as count')) 
->groupBy('date') ->get(['date', 'count']) ->keyBy('date') 

希望它能帮助!