如何循环访问Codeigniter中的每个用户的代码？

Question

我有计算员工总工时的代码。 我提供了登录条目数组和登出数组。因此，该代码计算员工工作的总小时数，秒数和最小值。

这是代码：

<?php 
       $loginarry = $attendances; 
       $logoutarry =$attendances_logouts; 
       $timeduration=0; 
       $login_i=0; 
       $logout_i=0; 


       echo '<table border="1px" class="table table-striped table-bordered table-hover" id="dataTables-example">'; 
       echo '<tr><th>Login</th><th>Logout</th><th>Duration</th></tr>'; 

       //echo ("Array Length = " . count($loginarry)." & ".count($logoutarry)."\n<br/>"); 
     while(true) 
     { 
      if($login_i >= count($loginarry) && $logout_i >= count($logoutarry)) 
       break; 

      if($logout_i >= count($logoutarry)) 
      { 
       //echo ("Login[".$login_i."] : ".$loginarry[$login_i]->date_data." and Logout : -----------------\n<br/>"); 


echo ("<tr><td>".$loginarry[$login_i]->date_data." </td><td>Not Available</td><td>Not Available</td></tr>"); 


    //   echo ("<tr> <td>".$loginarry->date_data." </td><td> Data Not Available</td></tr>"); 
       $login_i++; 
       continue; 
      } 

      if(($login_i+1) == count($loginarry) && ($logout_i+1) < count($logoutarry)) 
      { 
       echo ("<tr><td>Data Not Available </td><td>".$logoutarry[$logout_i]->date_data."\n</td><td>Data Not Available</td></tr>"); 
      $logout_i++; 
      continue; 
      } 

      if($login_i >= count($loginarry)) 
      { 
       echo ("<tr><td> Data Not Available </td><td>".$logoutarry[$logout_i]->date_data."\n<td>Data Not Available</td></td></tr>"); 
          $logout_i++; 
       continue; 
      } 
      //echo("******* ".(new DateTime($loginarry[$login_i+1]->date_data))->format('U') . " **** ".(new DateTime($logoutarry[$logout_i]->date_data))->format('U'). "\n<br/>"); 

      //check if next login time is smaller then current logout time - if so skip current login time 
      if($login_i < (count($loginarry)-1) && (new DateTime($logoutarry[$logout_i]->date_data))->format('U') > (new DateTime($loginarry[$login_i+1]->date_data))->format('U')) 
      //if(date_diff(date_create($logoutarry[$logout_i]->date_data), date_create($loginarry[$login_i+1]->date_data)) > 0) 
      { 
       echo ("<tr><td>".$loginarry[$login_i]->date_data."</td><td>Data Not Available</td><td>Data Not Available</td></tr>"); 
       $login_i++; 
       continue; 
      } 

      // 
      if((new DateTime($loginarry[$login_i]->date_data))->format('U') > (new DateTime($logoutarry[$logout_i]->date_data))->format('U')) 
      //if(date_diff(date_create($loginarry[$login_i]->date_data), date_create($logoutarry[$logout_i]->date_data)) > 0) 
        { 
       echo ("<tr><td>Data Not Available </td><td>".$logoutarry[$logout_i]->date_data."\n</td><td>Data Not Available</td></tr>"); 

          $logout_i++; 
          continue; 
        } 

      //if more logout entries then skip to last logout entry 
      if($login_i < (count($loginarry)-1) && $logout_i < (count($logoutarry)-1) && (new DateTime($logoutarry[$logout_i+1]->date_data))->format('U') < (new DateTime($loginarry[$login_i+1]->date_data))->format('U')) 
      { 
       echo(" <tr><td> Data Not Available</td> <td>".$logoutarry[$logout_i]->date_data."\n</td> <td>Data Not Available</td> </tr>"); 
          $logout_i++; 
          continue; 
      } 

      echo ("<tr><td> ".$loginarry[$login_i]->date_data."</td> <td>".$logoutarry[$logout_i]->date_data."</td>"); 




      $singleduration = ((new DateTime($logoutarry[$logout_i]->date_data))->format('U') - (new DateTime($loginarry[$login_i]->date_data))->format('U')); 
      if($singleduration > 43200)//12 hours X 3600 seconds) 
      { 
       //$timeduration += $singleduration; 
       echo ("<td class='danger'>Huge duration - not considered - please contact HR (".$singleduration.")</td></tr>"); 
      } 
      else 
      { 
       $timeduration += $singleduration; 
       echo ("<td>".gmdate("H:i:s",$singleduration)."</td></tr>"); 
      } 
      $login_i++; 
      $logout_i++; 

     } 

      echo ("</table>"); 

      //$finaltime=gmdate("H:i:s",$timeduration); 
      //$timedurationstr = ConvertSecondsToStr($timeduration); 
      $hours = 0; 
      if($timeduration > 3600) 
      { 
       $hours = floor($timeduration/3600); 
       $timeduration -= (3600*$hours); 
      } 
      $min = 0; 
      if($timeduration > 60) 
      { 
       $min = floor($timeduration/60); 
       $timeduration -= (60*$min); 
      } 
      $seconds = $timeduration; 



      //echo("<div class= 'row'> <div class ='col-sm-4' style= 'float:right'><h3 class='alert alert-success'><center>Total Hours Worked ". $finaltime." Hours</center></h3></div></div>"); 
      echo("<div class= 'row'> <div class ='col-sm-4' style= 'float:right'><h3 class='alert alert-success'><center>Total time worked: ". $hours." Hour(s) ".$min." Minute(s) ".$seconds." Second(s)</center></h3></div></div>"); 
      //echo("<div class= 'row'> <div class ='col-sm-4' style= 'float:right'><h3 class='alert alert-success'><center>Total time worked: ". $timedurationstr." </center></h3></div></div>"); 

       ?> 

所以最后它返回一个雇员的工作时间。这个代码在我看来。

现在我想为我的数据库中的每个用户计算这些值。 我不知道如何循环所有用户并运行此代码，以便我可以获取每个用户的总工作时间。

在控制器我获取用户和登录和登出这样的条目。

$users = $this->data['users'] = $this->user_m->get(); 


    $loginarry = $this->data['attendances'] = $this->attendance_m->all_login(); 
    $logoutarry =$this->data['attendances_logouts'] =$this->attendance_m->all_logout(); 

     $this->data['subview'] = 'admin/dashboard/index'; 
     $this->load->view('admin/_layout_main',$this->data); 

现在如何显示每个用户的总工作时间？

这是我的代码来获取登录和注销条目

ublic function all_login($emp_id = NULL) 
{ 



     $startDate = new DateTime("first day of last month"); 

     $endDate = new DateTime("last day of last month"); 

     $emp_id = $this->session->userdata('emp_id'); 

     $this->db->select('*'); 

     $this->db->from('daily_data2'); 


     $this->db->where('entry >','100'); 

     $this->db->where("date(date_data) BETWEEN '" . $startDate->format('Y-m-d') . "' AND '" . $endDate->format('Y-m-d') . "' "); 

     $this->db->order_by("date_data","ASC"); 



     $query = $this->db->get(); 

     $res = $query->result();   

     return $res; 

} 




public function all_logout() 
{ 


      $startDate = new DateTime("first day of last month"); 


      $endDate = new DateTime("last day of last month"); 



      $emp_id = $this->session->userdata('emp_id'); 

      $this->db->select('*'); 

      $this->db->from('daily_data2'); 



      $this->db->where('entry <','100'); 
      $this->db->where("date(date_data) BETWEEN '" . $startDate->format('Y-m-d') . "' AND '" . $endDate->format('Y-m-d') . "' "); 

      $this->db->order_by("date_data","ASC"); 



      $query = $this->db->get(); 



      $res = $query->result();   

      return $res; 


} 

Answer 1

如果这是你如何计算的时候，也许你应该做一个函数出席作为参数。然后你就可以得到用户的出席者名单和循环它

public function calculatedTime(attendance){ 

//Your coding here 

} 

，并可以循环它得到的时间

foreach($loginarry as $att){ 

    $this->calculatedTime($att); 

} 

尽量使编码尽可能简单，如果必要重复，只需创建一个函数并调用它即可。