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错误我在Java中得到了下一个简单的程序,我知道了网上,因为我尝试学习Java,但不知道如何解决它:的JComboBox在Java中,声明
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class java2 extends JPanel {
public java2() {
setLayout(new Gridlayout(2,1));
JList lista = new JList(java2.ids);
add(new JScrollpane(lista));
JComboBox combo=new JComboBox();
for (int i=0;i<100 ;i++) {
combo.addItem(Integer.toString(i));
add(combo);
}
}
public static void main(String args[]) {
java1 lista=new Java1();
JFrame ventana=new JFrame();
ventana.getContentPane().add(lista,BorderLayout.CENTER);
ventana.addWindowListener(new WindowAdapter(){public void windowClosing(WindowEvent evt){System.exit(0);}});
ventana.setSize(200,200);
ventana.setVisible(true);
}
}
即时得到下一问题我每次编译,就像我说的时候,即时通讯新的Java和可以说,我知道如何解决EM:
java2.java:8: error: cannot find symbol
setLayout(new Gridlayout(2,1));
^
symbol: class Gridlayout
location: class java2
java2.java:9: error: cannot find symbol
JList lista = new JList(java2.ids);
^
symbol: variable ids
location: class java2
java2.java:10: error: cannot find symbol
add(new JScrollpane(lista));
^
symbol: class JScrollpane
location: class java2
java2.java:18: error: cannot find symbol
java1 lista=new Java1();
^
symbol: class java1
location: class java2
java2.java:18: error: cannot find symbol
java1 lista=new Java1();
^
symbol: class Java1
location: class java2
Note: java2.java uses unchecked or unsafe operations.
Note: Recompile with -Xlint:unchecked for details.
5 errors
不应该有是**新的JScrollPane **?标记大写字母'P' –
错误专门告诉你这个问题。它找不到符号,因为你错误地指定了它们。在java.awt中有一个'GridLayout'而不是'Gridlayout'(注意大小写不同)。你其他的问题几乎相似:) – Sujay