strtok只在指定的分隔符上不能标记

Question

所以我是C的新手，并且在自学字符串处理。就我所能说的而言，我的问题是我的函数标记sp？输入的数字串不仅在空间上劈开。例如：如果我输入的数字是45，那么数组中的结果字符串将显示45和5，所以在两位数字中，无论出于何种原因，它都会分割数字。我搜查了很长时间，但没有任何运气。

希望这不是一个明显的错误，我只是俯瞰。但是我已经达到了无法继续学习的地步，所以我们不胜感激！

输出示例：

please enter your string: 1 45 30 82 
converting strings to ints 
Printing the string 
1, 0, 45, 5, 0, 30, 0, 0, 82, 2, 
Press any key to continue . . . 

我的代码：

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 
#include <math.h> 
#include <assert.h> 

#define STRING_LENGTH 81 
#define MAX_TOKENS 40 

int StrInput(char dataStr[]); 
void atoiWorker(char dataStr[], char results[], int idx); 
void printer (char dataStr[], int idx); 
void tokenize (char dataStr[], char results[]); 

int main() 
{ 
    int idx; 
    char dataStr[STRING_LENGTH]; 
    char results[STRING_LENGTH]; 
    idx = StrInput(dataStr); 
    tokenize(dataStr, results); 
    atoiWorker(dataStr, results, idx); 
    printer(results, idx); 
} 

int StrInput(char dataStr[]) 
{ 
    int idx = 0; 
    printf("please enter your string: "); 
    while (idx < (STRING_LENGTH) && ((dataStr[idx] = getchar()) != '\n')) 
     idx++; 

    dataStr[idx] = '\0'; 
    return idx; 
} 

void atoiWorker(char dataStr[], char results[], int idx) 
{ 
    int i; 
    printf("converting strings to ints\n"); 
    for (i = 0; i < idx; i++) 
     results[i] = atoi(&dataStr[i]); 
} 

void tokenize(char dataStr[], char *results[]) 
{ 
    int count = 0; 
    char delim[] = " ,\t\n"; //found this on msdn, hopefully it's right 

    if (results[0] = strtok(dataStr, " \t")) 
     count++; 

    while (results[count] = strtok(NULL, delim/*" \t"*/)) 
     count++; 
} 

void printer(char dataStr[], int idx) 
{ 
    int i; 
    printf("Printing the string\n"); 
    for (i = 0; i < idx; i++) 
     printf(" %d,", dataStr[i]); 
    printf("\n"); 
} 

Answer 1

设置results[]在tokenize()你再覆盖它在atioWorker()后。

Answer 2

修复此类

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 
#include <math.h> 
#include <assert.h> 

#define STRING_LENGTH 81 
#define MAX_TOKENS 40 

void StrInput(char dataStr[]); 
void atoiWorker(char *tokens[], int results[], int idx); 
void printer (int results[], int idx); 
int tokenize (char dataStr[], char *results[]); 

int main() 
{ 
    int idx; 
    char dataStr[STRING_LENGTH]; 
    char *tokens[MAX_TOKENS]; 
    int results[MAX_TOKENS]; 
    StrInput(dataStr); 
    idx = tokenize(dataStr, tokens); 
    atoiWorker(tokens, results, idx); 
    printer(results, idx); 
} 

void StrInput(char dataStr[]) 
{ 
    int idx = 0; 
    printf("please enter your string: "); 
    while (idx < (STRING_LENGTH) && ((dataStr[idx] = getchar()) != '\n')) 
     idx++; 

    dataStr[idx] = '\0'; 
} 

void atoiWorker(char *tokens[], int results[], int idx) 
{ 
    int i; 
    printf("converting strings to ints\n"); 
    for (i = 0; i < idx; i++) 
     results[i] = atoi(tokens[i]); 
} 

int tokenize(char dataStr[], char *results[]) 
{ 
    int count = 0; 
    char delim[] = " ,\t\n"; //found this on msdn, hopefully it's right 

    if (results[0] = strtok(dataStr, " \t")) 
     count++; 

    while (results[count] = strtok(NULL, delim/*" \t"*/)) 
     count++; 
    return count; 
} 

void printer(int result[], int idx) 
{ 
    int i; 
    printf("Printing the string\n"); 
    for (i = 0; i < idx; i++) 
     printf(" %d,", result[i]); 
    printf("\n"); 
}