2013-07-22 66 views
0

我一直在试用我的PHP技巧,看起来当我尝试从我的Android应用程序向PHP发送信息时,它似乎只发送参数名称(数据库显示:作为例如。)输出到数据库。我们使用PDO作为与MySQL数据库通信的方式。参数问题

这里是编码如下:

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) VALUES (':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')"; 

//Again, we need to update our tokens with the actual data: 
$query_params = array(
    ':Lname' => $_POST['LName'], 
    ':Fname' => $_POST['FName'], 
    ':Address' => $_POST['Address'], 
    ':City' => $_POST['City'], 
    ':State' => $_POST['State'], 
    ':ZIP' => $_POST['ZIP'], 
    ':Phone' => $_POST['Phone'], 
      ':myusername' => $_POST['username'], 
      ':mypassword' => $_POST['password'] 
); 

//time to run our query, and create the user 
try { 
    $stmt = $db->prepare($query); 
    $result = $stmt->execute($query_params); 
} 
catch (PDOException $ex) { 
    // For testing, you could use a die and message. 
    //die("Failed to run query: " . $ex->getMessage()); 

    //or just use this use this one: 
    $response["success"] = 0; 
    $response["message"] = $ex->getMessage(); 
    die(json_encode($response)); 
} 

回答

1

已包含在您的查询字符串文字值。

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) 
VALUES (':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')"; 

应该

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) 
VALUES (:Lname, :Fname, :Address, :City, :State, :ZIP, :Phone, :myusername, :mypassword)"; 
0

您需要从您的SQL值删除引号,因为它被解释为文字字符串。如果你删除它们,你应该都很好:)

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) VALUES (':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')";