如果某行不过去的一个过滤器

Question

我有一个查询

SELECT id, type FROM clients WHERE 1 GROUP BY id, type 

+----+------+ 
| id | type | 
+------+----+ 
| 1 | 1 | 
| 1 | 2 | 
| 1 | 3 | 
| 2 | 2 | 
| 2 | 3 | 
+----+------+ 

可以忽略结果的组，但我想忽略ID为“1”，因为这有一个1型，因此，在此情况下，我只是想有id为 “2”

谁能帮助我，谢谢

Answer 1

您可以使用NOT EXISTS：

SELECT id, type 
FROM clients AS c1 
WHERE NOT EXISTS (SELECT 1 
        FROM clients AS c2 
        WHERE c1.id = c2.id AND c2.type = 1) 

输出：

+----+------+ 
| id | type | 
+----+------+ 
| 2 | 2 | 
| 2 | 3 | 
+----+------+ 

Answer 2

一点点不同的语法：

SELECT distinct id, type 
FROM clients 
WHERE id not in (select distinct id from clients where type=1)