2014-11-21 103 views
-1

我有以下列表:如何使用scala在元组列表中查找字符串?

List(
    (List("vmname"),"myNetwork3",10,"vSwitch0",List(),"192.168.20.2","cisco WS-C3560E-48PD","GigabitEthernet0/43","sky"), 
    (List("vmname"),"myNetwork",0,"vSwitch0",List("name1", "name2", "name3", "name4"),"192.168.20.2","cisco WS-C3560E-48PD","GigabitEthernet0/43","sky") 
) 

而且我想找到列表列表元素串"name1"

我想下面的输出:

(List("vmname"),"myNetwork",0,"vSwitch0",List("name1", "name2", "name3", "name4"),"192.168.20.2","cisco WS-C3560E-48PD","GigabitEthernet0/43","sky") 

如何使用斯卡拉得到上面的输出?

+0

的第5个元素列表中的“名1”中的所有条目这是一个任务?有两个人问非常类似的问题 – 2014-11-21 13:32:13

+0

@paul不..我也找到类似的问题..我能够在列表中找到字符串,但无法在列表中找到它 – Yogesh 2014-11-21 13:34:27

回答

2
l.filter(._5 contains "name1") 

返回与属于每个条目

相关问题