双人免费或损坏：C++

因此，我从我的代码获得了内存泄漏错误：双人免费或损坏：C++

*** glibc detected *** ./KalmanFiltering: double free or corruption (!prev): 0x00000000015af7b0 *** 
======= Backtrace: ========= 
/lib/x86_64-linux-gnu/libc.so.6(+0x7eb96)[0x7f0897395b96] 
./KalmanFiltering[0x40654d] 
/lib/x86_64-linux-gnu/libc.so.6(__libc_start_main+0xed)[0x7f089733876d] 
./KalmanFiltering[0x4012b9] 
======= Memory map: ======== 
00400000-00415000 r-xp 00000000 00:15 6312794       /home/iggy/Dropbox/Documents/Research_Work/SimpleHealth/KalmanFilter/KalmanFilter_C++/cmpfit-1.2/KalmanFiltering 
00614000-00615000 r--p 00014000 00:15 6312794       /home/iggy/Dropbox/Documents/Research_Work/SimpleHealth/KalmanFilter/KalmanFilter_C++/cmpfit-1.2/KalmanFiltering 
00615000-00616000 rw-p 00015000 00:15 6312794       /home/iggy/Dropbox/Documents/Research_Work/SimpleHealth/KalmanFilter/KalmanFilter_C++/cmpfit-1.2/KalmanFiltering 
015ae000-01641000 rw-p 00000000 00:00 0         [heap] 
7f0897317000-7f08974cc000 r-xp 00000000 08:01 421630      /lib/x86_64-linux-gnu/libc-2.15.so 
7f08974cc000-7f08976cc000 ---p 001b5000 08:01 421630      /lib/x86_64-linux-gnu/libc-2.15.so 
7f08976cc000-7f08976d0000 r--p 001b5000 08:01 421630      /lib/x86_64-linux-gnu/libc-2.15.so 
7f08976d0000-7f08976d2000 rw-p 001b9000 08:01 421630      /lib/x86_64-linux-gnu/libc-2.15.so 
7f08976d2000-7f08976d7000 rw-p 00000000 00:00 0 
7f08976d7000-7f08976ec000 r-xp 00000000 08:01 395568      /lib/x86_64-linux-gnu/libgcc_s.so.1 
7f08976ec000-7f08978eb000 ---p 00015000 08:01 395568      /lib/x86_64-linux-gnu/libgcc_s.so.1 
7f08978eb000-7f08978ec000 r--p 00014000 08:01 395568      /lib/x86_64-linux-gnu/libgcc_s.so.1 
7f08978ec000-7f08978ed000 rw-p 00015000 08:01 395568      /lib/x86_64-linux-gnu/libgcc_s.so.1 
7f08978ed000-7f08979e8000 r-xp 00000000 08:01 422139      /lib/x86_64-linux-gnu/libm-2.15.so 
7f08979e8000-7f0897be7000 ---p 000fb000 08:01 422139      /lib/x86_64-linux-gnu/libm-2.15.so 
7f0897be7000-7f0897be8000 r--p 000fa000 08:01 422139      /lib/x86_64-linux-gnu/libm-2.15.so 
7f0897be8000-7f0897be9000 rw-p 000fb000 08:01 422139      /lib/x86_64-linux-gnu/libm-2.15.so 
7f0897be9000-7f0897ccb000 r-xp 00000000 08:01 531352      /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.16 
7f0897ccb000-7f0897eca000 ---p 000e2000 08:01 531352      /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.16 
7f0897eca000-7f0897ed2000 r--p 000e1000 08:01 531352      /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.16 
7f0897ed2000-7f0897ed4000 rw-p 000e9000 08:01 531352      /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.16 
7f0897ed4000-7f0897ee9000 rw-p 00000000 00:00 0 
7f0897ee9000-7f0897f0b000 r-xp 00000000 08:01 422388      /lib/x86_64-linux-gnu/ld-2.15.so 
7f08980a3000-7f08980ea000 rw-p 00000000 00:00 0 
7f0898107000-7f089810b000 rw-p 00000000 00:00 0 
7f089810b000-7f089810c000 r--p 00022000 08:01 422388      /lib/x86_64-linux-gnu/ld-2.15.so 
7f089810c000-7f089810e000 rw-p 00023000 08:01 422388      /lib/x86_64-linux-gnu/ld-2.15.so 
7fffc58ae000-7fffc58cf000 rw-p 00000000 00:00 0       [stack] 
7fffc59af000-7fffc59b0000 r-xp 00000000 00:00 0       [vdso] 
ffffffffff600000-ffffffffff601000 r-xp 00000000 00:00 0     [vsyscall] 
Aborted (core dumped)

运行在gdb where我得到：

#0 0x00007ffff723e425 in __GI_raise (sig=<optimized out>) at ../nptl/sysdeps/unix/sysv/linux/raise.c:64 
#1 0x00007ffff7241b8b in __GI_abort() at abort.c:91 
#2 0x00007ffff727c39e in __libc_message (do_abort=2, fmt=0x7ffff7386748 "*** glibc detected *** %s: %s: 0x%s ***\n") at ../sysdeps/unix/sysv/linux/libc_fatal.c:201 
#3 0x00007ffff7286b96 in malloc_printerr (action=3, str=0x7ffff7386858 "double free or corruption (!prev)", ptr=<optimized out>) at malloc.c:5039 
#4 0x000000000040654d in main (argc=6, argv=0x7fffffffe0c8) at KalmanFiltering.cpp:828

，其中828是在返回行我main()功能。有问题的代码是：

int main(){ 
    ... 
    EKSmoothParams *EKParams = new EKSmoothParams; 
    prepareSmoother(optPar, ECGsd, peaks, phase, x, fs, EKParams); 

    delete EKParams; 

    return 0; 
} 

void prepareSmoother(vector<double> optPar, vector<double> ECGsd, vector<double> peaks, vector<double> phase, vector<double> x, double fs, EKSmoothParams *params){ 
    const int N = PEAK_NUM; // number of Gaussian kernels                               
    vector<int> JJ; 
    JJ.reserve(peaks.size()); 
    for(int i = 0; i < peaks.size(); i++){ 
    if(peaks.at(i) != 0) 
     JJ.push_back(i); 
    } 
    vector<double> fm; // heart-rate                                    
    fm.reserve(JJ.size()-1); 
    for(int i = 0; i < JJ.size()-1; i++){ 
    fm.push_back(fs/(JJ.at(i+1)-JJ.at(i))); 
    } 
    vector<double> twoPiFm = fm; 
    for(int i = 0; i < fm.size(); i++) 
    twoPiFm[i] = 2*PI*fm.at(i); 

    double w = calculateMean(twoPiFm);   // average heart-rate in rads.                         
    double wsd = sd2(twoPiFm);  // heart-rate standard deviation in rads.                          

    params->X0[0][0] = 1.0; 
    params->X0[0][1] = -PI; 
    params->X0[1][0] = 1.0; 
    params->X0[1][1] = 0.0; 

    params->P0[0][0] = pow(2*PI,2); 
    params->P0[0][1] = 0.0; 
    params->P0[1][0] = 2.0; 
    params->P0[1][1] = 10*pow(findAbsMax(x),2.0); 

    vector<double> diagonal(3*N+2, 0.0); 
    for(int i = 0; i < N; i++) 
    diagonal[i] = pow(0.1*optPar.at(i),2.0); 
    for(int i = N; i < 3*N; i++) 
    diagonal[i] = pow(0.5,2.0); 
    diagonal[3*N] = pow(wsd,2.0); 
    vector<double>::const_iterator first = ECGsd.begin(); 
    vector<double>::const_iterator last = ECGsd.begin() + round(ECGsd.size()/10.0); 
    vector<double> ECGsdPartial(first, last); 
    displayVector(ECGsd); 
    diagonal[3*N+1] = pow(0.05*calculateMean(ECGsdPartial), 2.0); 

    for(int i = 0; i < diagonal.size(); i++) 
    params->Q[i][i] = diagonal[i]; 

    params->R[0][0] = pow(w/fs,2)/12.0;; 
    params->R[0][1] = 0.0; 
    params->R[1][0] = 0.0; 
    params->R[1][1] = pow(calculateMean(ECGsdPartial), 2.0); 

    for(int i = 0; i < optPar.size(); i++){ 
    params->wMean[i] = optPar.at(i); 
    params->inits[i] = optPar.at(i); 
    } 
    params->wMean[N*3] = w; 
    params->wMean[N*3+1] = 0; 
    params->inits[N*3] = w; 
    params->inits[N*3+1] = fs; 

    params->vMean[0] = 0.0; 
    params->vMean[1] = 0.0; 

    params->inovWlen = round(0.5*fs+0.5); 
    params->tau = 0; 
    params->gamma = 1; 
    params->rAdaptWlen = round(fs/2.0 + 0.5); 
    params->flag = 1; 

    for(int i = 0; i < 2; i++){ 
    for(int j = 0; j < 2; j++){ 
     cout << params->R[i][j] << " "; 
    } 
    } 
}

而且结构是静态分配：

struct EKSmoothParams { 
    int tau; 
    int gamma; 
    int flag; 
    int inovWlen; 
    int rAdaptWlen; 

    double wMean[3*PEAK_NUM+2]; 
    double vMean[2]; 
    double inits[3*PEAK_NUM+2]; 

    double X0[2][2]; 
    double P0[2][2]; 
    double Q[3*PEAK_NUM+2][3*PEAK_NUM+2]; 
    double R[2][2]; 
};

其中：

#define MEAN_PEAK_NUM_HIGH 3 
#define MEAN_PEAK_NUM_LOW 3 
#define PEAK_NUM MEAN_PEAK_NUM_HIGH+MEAN_PEAK_NUM_LOW

任何帮助将不胜感激。我认为如果一个结构是静态分配的，那么只能调用

delete struct_name;

会删除引用。谢谢您的帮助！

UPDATE：

所以我跑Valgrind的，它告诉我要删除delete EKParms。我删除了delete EKParms线，并再次运行它：

valgrind --leak-check=full ./KalmanFiltering x.txt pphase.txt phase.txt opt.txt peaks.txt

和输出我得到的是：

==32755== Memcheck, a memory error detector 
==32755== Copyright (C) 2002-2011, and GNU GPL'd, by Julian Seward et al. 
==32755== Using Valgrind-3.7.0 and LibVEX; rerun with -h for copyright info 
==32755== Command: ./KalmanFiltering x.txt pphase.txt phase.txt opt.txt peaks.txt 
==32755== 
0.117777 0.102793 0.0911142 0.107277 0.109 0.126729 0.115012 0.109627 0.131102 0.100467 0.0822639 0.122442 0.0908527 0.116644 0.108093 0.104796 0.12665 0.102979 0.0999146 0.119981 0.107912 0.122379 0.113098 0.0889197 0.106954 0.101472 0.125473 0.107778 0.13228 0.10528 0.11511 0.107965 0.0961817 0.125068 0.12075 0.110846 0.120621 0.132226 0.106999 0.114672 0.0997654 0.104048 0.117857 0.105461 0.127318 0.11103 0.134415 0.12594 0.126633 0.116603 0.109422 0.117 0.130797 0.112808 0.113414 0.0951991 0.112291 0.109693 0.118444 0.104215 0.124635 0.0993083 0.122034 0.122363 0.12139 0.0969221 0.108173 0.109436 0.115881 0.118631 0.0968963 0.104841 0.118923 0.10789 0.108117 0.119053 0.115187 0.119369 0.089593 0.0893818 0.127805 0.109007 0.108001 0.128517 0.105524 0.117847 0.127699 0.101618 0.113646 0.112389 0.114674 0.108706 0.117413 0.119509 0.110195 0.116943 0.132244 0.108374 0.117175 0.114302 0.113753 0.127603 0.104102 0.112583 0.110015 0.102419 0.122587 0.104333 0.122883 0.129287 0.129104 0.10733 0.11312 0.125945 0.119181 0.128817 0.129468 0.114589 0.146289 0.135648 0.118936 0.146207 0.160105 0.167322 0.16074 0.140913 0.153806 0.178517 0.215381 0.251905 0.163988 0.137749 0.107549 0.121755 0.121141 0.0867208 0.103768 0.130058 0.142986 0.115026 0.12086 0.12443 0.122726 0.110762 0.125137 0.126337 0.0953488 0.10774 0.112677 0.116888 0.115948 0.104844 0.114403 0.121069 0.110119 0.0980817 0.109335 0.104094 0.10667 0.118813 0.123157 0.11163 0.105456 0.103909 0.112385 0.126633 0.123956 0.108601 0.113358 0.0971531 0.123609 0.116769 0.130958 0.103691 0.114814 0.116871 0.12273 0.116116 0.118833 0.11895 0.100572 0.128861 0.110058 0.121104 0.122787 0.122287 0.114645 0.12352 0.122679 0.121228 0.116913 0.128488 0.111704 0.102892 0.119502 0.113897 0.144082 0.132502 0.115685 0.145348 0.137543 0.12479 0.132752 0.137675 0.144116 0.127518 0.146219 0.152045 0.123085 0.152635 0.153129 0.159488 0.139282 0.150634 0.119596 0.1195 0.127458 0.109524 0.106355 0.116666 0.114375 0.104727 0.0978894 0.0941401 0.11789 0.11224 0.110342 0.106331 0.104715 0.0991576 0.116447 0.0908483 0.11542 0.105876 0.0955746 0.120995 0.125514 0.130953 0.12472 0.118668 0.118989 0.106662 0.117213 0.111635 0.106181 0.11708 0.101769 0.10301 0.112952 0.104064 
3.31532e-06 0 0 0.0118791 
==32755== 
==32755== HEAP SUMMARY: 
==32755==  in use at exit: 0 bytes in 0 blocks 
==32755== total heap usage: 61,624 allocs, 61,624 frees, 6,091,874 bytes allocated 
==32755== 
==32755== All heap blocks were freed -- no leaks are possible 
==32755== 
==32755== For counts of detected and suppressed errors, rerun with: -v 
==32755== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 2 from 2)

然而，当我运行该程序通常我仍然得到双重释放或腐败误差之前。

来源

2014-07-07 ryan

下'的valgrind --leak检查=全运行程序your_program'。很可能你的记忆腐败发生在别的地方。 –

@ dandan78有一个'新'。 –

@EitanT哎呀，谢谢，错过了。 – dandan78

问题可能是内存损坏。你有错误#define PEAK_NUM。需要括号：

#define PEAK_NUM (MEAN_PEAK_NUM_HIGH+MEAN_PEAK_NUM_LOW)

没有这些额外的括号，你比如这个：

double Q[3*MEAN_PEAK_NUM_HIGH+MEAN_PEAK_NUM_LOW+2][3*MEAN_PEAK_NUM_HIGH+MEAN_PEAK_NUM_LOW+2];

而这显然比预期的要少得多，所以你的功能可能破坏内存，任何事情都有可能之后发生的。

开始修复！另外，这也证明了为什么宏是邪恶的。使用它们时必须非常小心，即使是经验丰富的程序员，他们偶尔也会遇到。

尽管这是出了问题的范围，这里的更安全地定义常量一个方式：

enum { 
    MEAN_PEAK_NUM_HIGH = 3, 
    MEAN_PEAK_NUM_LOW = 3, 
    PEAK_NUM = MEAN_PEAK_NUM_HIGH + MEAN_PEAK_NUM_LOW 
};

来源

2014-07-07 07:03:55 hyde

宾果！那会让我永远注意......谢谢！ – ryan

双人免费或损坏：C++

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