在Ruby中，如何根据键中的单词数量对散列中的元素进行排序？

Question

例如：

{"job" => 1, "big job" => 2, "super job" => 1, "work" => 2, "super big job" => 1} 

我想变成像这样

{"super big job" => 1, "big job" => 2, "super job" => 1, "job" => 1, , "work" => 2} 

即三个词键先走，然后双字键，一个字键走过去。 我知道我可以使用key.split（''）.length函数来计算单词，但我怎样才能使用它来实际修改哈希中元素的顺序。

Answer 1

你可以做这样的事情：

a = {"job" => 1, "big job" => 2, "super job" => 1, "work" => 2, "super big job" => 1} 
Hash[a.sort_by { |k, v| k.split.size }.reverse] 
# => {"super big job"=>1, "super job"=>1, "big job"=>2, "work"=>2, "job"=>1} 

Answer 2

x = {"job" => 1, "big job" => 2, "super job" => 1, "work" => 2, "super big job" => 1} 

p x.sort_by{|x,|-x.split.size}.to_h #=> {"super big job"=>1, "big job"=>2, "super job"=>1, "work"=>2, "job"=>1}