当我启用优化(标志-O2/-03)时,为什么此代码会生成段错误。 在返回之前添加断言时,那么一切OK。启用优化时发生g ++分段错误
#include <iostream>
#include <typeinfo>
#include <vector>
#include <assert.h>
struct doublet {
doublet(double val1 = 0, double val2 = 0) {
dob[0] = val1;
dob[1] = val2;
}
template< class Expr >
doublet& operator=(Expr const& x){
dob[0] = x[0];
dob[1] = x[1];
return *this;
}
const double& operator[](unsigned ix) const {
/*
* BUG HERE
*/
//assert(ix<2);
return dob[ix];
}
void print(){
std::cout << (*this)[0] << std::endl;
std::cout << (*this)[1] << std::endl;
}
private:
double dob[2];
};
struct plus {
static double apply(double a, double b) {
return a + b;
}
};
struct minus {
static double apply(double a, double b){
return a - b;
}
};
template <class L, class OpTag, class R>
struct Expression {
Expression (L const& l, R const& r) :l(l),r(r){}
L const& l;
R const& r;
typedef const double result_type;
result_type operator[](unsigned ix) const {
return OpTag::apply(l[ix],r[ix]);
}
};
template <class L, class R>
Expression<L,plus,R> operator+(L const& l, R const& r){
return Expression<L,plus,R>(l,r);
}
template <class L, class R>
Expression<L,minus,R> operator-(L const& l, R const& r){
return Expression<L,minus,R>(l,r);
}
int main()
{
doublet a(4.0,1.0), b(5.1,3.3), c(7.4,5.2);
Expression<Expression<doublet, plus, doublet>, plus, doublet>
k = b + a + c;
std::cout << k[0] << " " << k[1] << std::endl;
}
Assembler instructions此代码。分割错误到达20行(edx = 0)。
UPDATE。我会弄清楚有什么问题。为了稳定工作,需要声明k为双峰或添加到表达类operator =。与L常量&的情况是不正确的,因为它创建模板对象(Herb Sutter约const引用rvalue)。
哪个编译器? g ++ 4.8.1编译这个罚款 –