总和后面的数字

Question

number = 96154# Replace ??? with a value of your choice. 
sequence_len = 3 # Replace ??? with a value of your choice. 
sum=0 
numbstr=str(number) 
digitlist=[] 

for digit in numbstr: 
digitlist.append(int(digit)) 

while sum!=10 or len(digitlis)<sequence_len: 
sum=0 
if len(digitlist)>=3: 
    for i in range(0,3): 
     sum=sum+digitlist[i] 
    del digitlist [i] 

print sum 

的代码需要检查是否存在以下数字（例如3）的总和是10序列的总和，并打印信息吧

什么是错误的，我码？

Answer 1

两个问题：

1. ...len(digitlis)<sequence_len...，您的变量缺少t。其次，我不知道你的代码是做什么的，逻辑不是非常直观的。

但是，这里有一个简单的程序，已经做了你想让它做什么，我一直是尽可能简单：

number = 343703 # Replace ??? with a value of your choice. 
sequence_len = 3 # Replace ??? with a value of your choice. 
numbstr = str(number) 
digitlist = [] 

# Appending all the numbers to a list 
for digit in numbstr: 
    digitlist.append(int(digit)) 

# Looping over all the variables in digitlist, i is the index 
for i, _ in enumerate(digitlist): 
    # If the index, i is 2 less than the length of the list 
    if i < len(digitlist) - 2: 
     # Adding the term and the next two terms after that 
     if digitlist[i] + digitlist[i+1] + digitlist[i+2] == 10: 
      # Printing the list 
      print digitlist[i:i+3] 

Working example.

Answer 2

for循环后，i将是3.因此del digitlist [i]将删除第3个元素，而不是第1个元素。将其替换为del digitlist [0]。此外，您的while语句条件中的len(digitlis)<sequence_len应为len(digitlis)>=sequence_len。最后，有一个拼写错误; len(digitlis)应该是len(digitlist)。

更正代码：

number = 96154# Replace ??? with a value of your choice. 
sequence_len = 3 # Replace ??? with a value of your choice. 
sum=0 
numbstr=str(number) 
digitlist=[] 

for digit in numbstr: 
digitlist.append(int(digit)) 
# len(digitlis)<sequence_len → len(digitlist)>sequence_list 
while sum!=10 or len(digitlist)>sequence_len: # 
    sum=0 
    if len(digitlist)>=3: 
     for i in range(0,3): 
      sum=sum+digitlist[i] 
     del digitlist [0] # del digitlist [i] → del digitlist [0] 

print sum 

一个更紧凑的版本使用Python的特点：

DESIRED_SUM=10 
number = 96154# Replace ??? with a value of your choice. 
sequence_len = 3 # Replace ??? with a value of your choice. 
digit_list = list(map(int,str(number))) 
# Note that if len(digit_list)-sequence_len+1 is negative, the range function will return an empty list, making the generator comprehension empty. any() returns False on an empty iterator (a generator is an iterator). 
indexes = [i for i in range(len(digit_list)-sequence_len+1) if sum(digit_list[i:i+sequence_len])==DESIRED_SUM] 
if len(indexes) > 0: 
    print "{sequence_len} consecutive digits in {number} have a sum of {DESIRED_SUM}.".format(**vars()) 
else: 
    print "No {sequence_len} consecutive digits have a sum of {DESIRED_SUM}.".format(**vars()) 

Answer 3

首先：

digitlist=[] 

for digit in numbstr: 
digitlist.append(int(digit)) 

可以通过简单地更换：

digitlist = [int(i) for i in str(number)] 

要计算总和，只需拨打名单上的SUM函数：

sum(digitlist)