如何在不使用表单的情况下将数据从一个页面发送到另一个页面? 我得到的ID和类型由GET方法将数据从一个页面发送到另一个页面而不使用表单php
<a href="form.php?id=<?php echo $_GET['id']."&".$_GET['type']; ?>" class="orderbtn">Order Now</a>
当我去form.php的,我填写表格,然后点击提交按钮,我的表单页面代码如下
form.php的
<div id="form">
<p class="rf">*Required Fields </p>
<form action="formsubmitted.php" onsubmit="return formValidate()" method="post" name="myform">
<span class="required" title="Required Field">*</span>
<span style="font-size:16px; color:#000; font-family:Arial, Helvetica, sans-serif;">Name: </span>
<input id="name" title="Enter Your Full Name" type="text" name="name" autofocus="autofocus" required="required" value=""/><br/>
<span class="required" title="Required Field">*</span>
<span style="font-size:16px;color:#000; font-family:Arial, Helvetica, sans-serif;padding-right:10px;">Email:</span>
<input id="email" type="email" name="email" required="required" placeholder="[email protected]"/><br/>
<span class="required" title="Required Field">*</span>
<span style="font-size:16px;color:#000; font-family:Arial, Helvetica, sans-serif;">Address:</span>
<input id="address" title="Enter Address" type="text" name="address" required="required" value=""/><br/>
<span class="required" title="Required Field">*</span>
<span style="font-size:16px;color:#000; font-family:Arial, Helvetica, sans-serif;">Contact Number:</span>
<input id="contactno" title="Enter Number" type="text" name="contact" required="required" value=""/><br/>
<input id="submit" name="submit" type="submit" value="Submit"/></span>
</form>
</div>
当我提交不言而喻formsubmitted.php页面,在这里我使用POST方法,即把数据插入到数据库
formsubmitted.php
<?php
$connection = mysql_connect("localhost","root","");
$select_db = mysql_select_db("fashion",$connection);
if(!$connection)
{
die ("Could not Connect".mysql_error());
}
$query = "INSERT INTO `order` (flname,email,address,contact) VALUES ('{$_POST['name']}','{$_POST['email']}','{$_POST['address']}','{$_POST['contact']}');";
echo $query . "<br />";
$res = mysql_query($query,$connection);
if(!$res) {die("Could Not Enter Data".mysql_error());}
else { echo "Enter Data Successfully."; }
?>
我要插入的ID和类型的我在表单页面获得的网址我怎样才能去做?
我看到的'mysql_query'这两者都是不好的直列造型和用法网页设计实践。我认为你现在应该关心那些人。 – samayo
您的代码提供了一个如何构造危险的SQL查询的绝佳示例。 http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php – Dave
是你两个权利,但下一次我肯定不会这样做设计 – shani