我有一个one2many它存储一些数据。OpenERP - many2one删除旧数据
在python,当我需要更新对象.write方法;新的数据被存储,但旧的东西仍然存在。
如何在使用之前清空many2many .write方法??
也许使用.browse和.search ??请帮忙 !!!
我有一个one2many它存储一些数据。OpenERP - many2one删除旧数据
在python,当我需要更新对象.write方法;新的数据被存储,但旧的东西仍然存在。
如何在使用之前清空many2many .write方法??
也许使用.browse和.search ??请帮忙 !!!
如果您发布了一些您正在尝试做的事情,那将会很棒。无论如何,你有2个解决方案:
unlink()
write()
ORM方法是如何工作的one2many
领域。我们以account.invoice
和account.invoice.line
为例。
第一种方法 - unlink()
:
def delete_lines(self, cr, uid, ids, context=None):
invoice_pool = self.pool.get('account.invoice')
line_pool = self.pool.get('account.invoice.line')
for invoice in invoice_pool.browse(cr, uid, ids, context=context):
line_ids = [line.id for line in invoice.invoice_line]
line_pool.unlink(cr, uid, line_ids, context=context)
第二种方法 - write()
望着OpenERP的文档(https://doc.openerp.com/6.0/developer/2_5_Objects_Fields_Methods/methods/#osv.osv.osv.write):
write(cr, user, ids, vals, context=None)
...
Note: The type of field values to pass in vals for relationship fields is specific:
For a one2many field, a lits of tuples is expected. Here is the list of tuple that are accepted, with the corresponding semantics
(2, ID) remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
所以对于vals
paramete [R,我们需要一个元组列表中的格式如下:
[
(2, line1_id),
(2, line2_id),
(2, line3_id),
...
]
下面的代码说明了write()
方法。
def delete_lines(self, cr, uid, ids, context=None):
invoice_pool = self.pool.get('account.invoice')
for invoice in invoice_pool.browse(cr, uid, ids, context=context):
vals = [(2, line.id) for line in invoice.invoice_line]
invoice.write(vals)
我没有测试这些例子,所以让我知道他们是否做这项工作。
这是我如何解决它:
my_object = self.pool.get('my.main.object')
props = self.pool.get('table.related')
prop_id = props.search(cr, uid, [('id_1', '=', id_2)])
del_a = []
for p_id in prop_id:
del_a.append([2, p_id])
my_object.write(cr, uid, line_id, {'many2one_field': del_a}, context=context)
其中: del_a.append([2的p_id])创建了代码的元组字符串 “2”(删除) 和my_object是我需要进行更改的地方。
谢谢你的答案;我发布了我是如何解决它的,这几乎是你的第二选择。 –