嵌套的MySQL查询

Question

我一直在试图为公共交通系统编写一个查询，当我输入起点和终点站号时，它将输出路线列表。

这里是我的MySQL表：

mysql> desc route_timings; 
+----------------+---------+------+-----+---------+----------------+ 
| Field   | Type | Null | Key | Default | Extra   | 
+----------------+---------+------+-----+---------+----------------+ 
| ID    | int(11) | NO | PRI | NULL | auto_increment | 
| route_number | int(11) | NO |  | NULL |    | 
| stop_number | int(11) | NO |  | NULL |    | 
| arrival_time | time | YES |  | NULL |    | 
| departure_time | time | YES |  | NULL |    | 
+----------------+---------+------+-----+---------+----------------+ 
5 rows in set (0.00 sec) 

下面是样本值：

mysql> select * from route_timings; 
+----+--------------+-------------+--------------+----------------+ 
| ID | route_number | stop_number | arrival_time | departure_time | 
+----+--------------+-------------+--------------+----------------+ 
| 1 |   54 |   1 | 10:00:00  | 10:05:00  | 
| 2 |   54 |   2 | 11:00:00  | 11:05:00  | 
| 3 |   54 |   3 | 12:00:00  | 12:05:00  | 
| 4 |   55 |   3 | 13:00:00  | 13:05:00  | 
| 5 |   55 |   4 | 14:00:00  | 14:05:00  | 
| 6 |   55 |   5 | 15:00:00  | 15:05:00  | 
| 7 |   60 |   3 | 10:00:00  | 10:05:00  | 
| 8 |   60 |   2 | 11:00:00  | 11:05:00  | 
| 9 |   60 |   1 | 12:00:00  | 12:05:00  | 
+----+--------------+-------------+--------------+----------------+ 
9 rows in set (0.01 sec) 

我的问题是：如果我想列出ROUTE_NUMBER的，将包含stop_number 1和stop_number 3，我会写类似这样的查询：

SELECT DISTINCT `route_number` FROM `route_timings` WHERE `route_number` IN (
    SELECT `route_number` FROM `route_timings` WHERE `stop_number`=1 
) AND `route_number` IN (
    SELECT `route_number` FROM `route_timings` WHERE `stop_number`=3 
); 

但是，上面的查询只会返回包含两个站点的route_number，而不是源站点（1）在目标站点（3）之前到达的路线。

查询将返回以下：

+--------------+ 
| route_number | 
+--------------+ 
|   54 | 
|   60 | 
+--------------+ 

的ROUTE_NUMBER 60不会从1开始，到3，而是从3开始并且前往1.是否有人可以帮助我，有点添加到查询以便查询仅输出其中stop_number 1的到达时间小于stop_number 3的到达时间的route_number。

在此先感谢。 -Shain

Answer 1

做了如何像重命名为联合收割机querys工作表约定我习惯了，但原则应该清楚

Answer 2

用途：

SELECT DISTINCT `route_number` FROM `route_timings` WHERE `stop_number` IN (1,3) 

注：为什么DEPARTURE_TIME为>比ARRIVAL_TIME？

Answer 3

SELECT DISTINCT `route_number` R1 FROM R1.`route_timings` WHERE R1.`stop_number` =3 AND R1.`route_number` IN (
SELECT `route_number` R2 FROM `route_timings` WHERE R2.`stop_number`=1 AND R2.`arrival_time` > R1.`arrival_time` 
); 

我现在不能尝试，但我希望语法是正确的。我所做的是选择经过3的路线，然后检查他们是否稍后停在1。这是使用SQL Server的语法和名称

select fromStop.RouteNumber 
from routeTimings fromStop 
    inner join routeTimings toStop on toStop.RouteNumber = fromStop.RouteNumber and toStop.StopNumber = 3 and toStop.ArrivalTime > fromStop.DepartureTime 
where fromStop.StopNumber = 1 

注意调整为：我通常使用SQLite，让像我在SELECT route_number R2