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我在Ms Access中使用下面的查询。这给了我错误Syntax error in your query expression CASE WHEN not ...
。你能告诉我我做错了什么吗?在Sql Server 2008 R2中,case
语句正确运行。MS Access查询中的case语句给出错误
SELECT TableApron.RadButtonNo, TableApron.ShortName, QueryForNot1.InspectionDate, QueryForNot1.Findings, QueryForNot1.Status, QueryForNot1.Initials, TableApron.DeptName, TableApron.Lost, TableApron.InServelDate, TableApron.RemovedDate, TableApron.PrivateUserName, TableApron.PrivateUserEmail, TableApron.ApronType, TableApron.Manufacturer
FROM TableApron LEFT JOIN QueryForNot1 ON TableApron.RadButtonNo=QueryForNot1.RadButtonNoI
WHERE (((TableApron.Lost)="N" Or (TableApron.Lost)=[@Lost]) And ((TableApron.InServelDate) Is Null Or (TableApron.InServelDate) Between CDATE([@From]) And CDATE([@To]) Or (TableApron.InServelDate)<CDATE([@To])) And ((TableApron.RemovedDate) Is Null Or (TableApron.RemovedDate) Between CDATE([@From]) And CDATE([@To]) Or (TableApron.RemovedDate)>CDATE([@To])))
ORDER BY
CASE
WHEN not TableApron.RadButtonNo like '%[^0-9]%' THEN CONVERT(int,TableApron.RadButtonNo)
WHEN TableApron.RadButtonNo like '[0-9]%' THEN CONVERT(int,SUBSTRING(TableApron.RadButtonNo,1,PATINDEX('%[A-Z]%',TableApron.RadButtonNo)-1))
END,
CASE
WHEN not TableApron.RadButtonNo like '%[^0-9]%' THEN NULL
WHEN TableApron.RadButtonNo like '[0-9]%' THEN SUBSTRING(TableApron.RadButtonNo,PATINDEX('%[A-Z]%',TableApron.RadButtonNo),9000)
ELSE TableApron.RadButtonNo
END;
CASE是T-SQL。用一个IIf(条件,真,假)表达式替换。 – Gustav