我正在django中创建一个表单,希望允许用户删除他们的一些设备。当我点击我的表单的提交按钮时,我不断收到消息:Select a valid choice. <Some choice> is not one of the available choices
。这是我的代码。非常感谢:)MultipleChoiceField - invalid_choice错误 - 选择一个有效的选项。 SomeChoice不是可用选项之一
forms.py
class DeleteDeviceForm(forms.Form):
devices = forms.MultipleChoiceField(widget=forms.CheckboxSelectMultiple)
views.py
def delete_device(request):
if request.method == 'POST':
deletedeviceform = DeleteDeviceForm(request.POST)
if deletedeviceform.is_valid():
devicelist = request.POST.getlist('devices')
#will put other stuff there to process the data later, just want to access list now
return HttpResponseRedirect('/accounts/loggedin', {"devicelist": devicelist, })
else: #if not a POST request
userid = request.user.profile.pk
devices = Device.objects.filter(user_id=userid)
deletedeviceform = DeleteDeviceForm()
deletedeviceform.fields['devices'].choices = [(x.id, x) for x in devices]
return render(request, 'userprofile/delete_device.html', {"full_name": request.user.username, "deletedeviceform": deletedeviceform,})
需要注意的是:我没有一个模型,这种形式
好,谢谢你的建议,这是一个很好的起点! :)但是,我知道我应该有这样的东西, def __init __(self,* args,** kwargs): super(DeleteDeviceForm,self).__ init __(* args,** kwargs) self.queryset = Device.objects.filter(user_id = ????) 我不知道我应该如何让我的用户ID在该窗体内......任何关于如何编码的建议?非常感谢:) – Rose
你需要从视图中传递它,并从* args或** kwargs中获取它。 –