我试图返回用户名与数据库表中的用户名匹配的行数组。 JSON结果只是给了我最后一行。从数据库表中获取行android
示例表:
james 14 [email protected]
mah 12 [email protected]
james 23 [email protected]
result gives me:
23 [email protected]
,但我想詹姆斯都排不只是最后一个。 所以无论14 [email protected]和23 [email protected] 感谢
我的PHP代码:
<?php
$username = $_POST["username"];
$con = new mysqli("xx", "xx", "xx", "xx");
// selects everything
$statement = mysqli_prepare($con, "SELECT * FROM `user` WHERE username = ?");
mysqli_stmt_bind_param($statement, "s", $username);
mysqli_stmt_execute($statement);
// Store the result to use
mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statement, $id, $username, $age, $email);
// Get results returned and put in array
$user = array();
while (mysqli_stmt_fetch($statement)) {
$user[age] = $age;
$user[email] = $email;
}
// Send array back to phone
print (json_encode($user));
mysqli_stmt_close($statement);
mysqli_close($con);
?>