SQL子查询：不返回行

Question

我挣扎在SQL查询过滤条目...我有三个表：

1）工作

2）paper1

3）paper2

paper1和paper2有一个列表job_id其中引用了相应的作业ID;所以具有编号的工作具有paper1.job_id的。

现在，我希望看到有相应的paper1但没有paper2所有作业（这样的：未完成的，因为paper1和paper2是这个职位的要求得到满足）。我的尝试是这样的，但它没有正确工作：

SELECT id 
FROM jobs 
WHERE (SELECT id FROM paper1 WHERE (job_id = jobs.id) != 0 LIMIT 1) 
AND (SELECT id FROM paper2 WHERE (job_id = jobs.id) = NULL LIMIT 1) 

任何帮助表示赞赏;谢谢。

Answer 1

尝试作业：

Select job_id 
FROM paper1 
WHERE job_id NOT IN (Select job_id from paper2 group by paper2) 

GROUP BY job_id; 

Answer 2

select id 
from jobs 
where exists (select p1.id from paper1 as p1 where p1.job_id = jobs.id) 
    and not exists (select p2.id from paper2 as p2 where p2.job_id = jobs.id) 

Answer 3

根据我的理解，我认为你只想要其中仅在paper1但不是在paper2 如果多数民众赞成的要求，然后尝试下面的代码

select * from jobs where id in (select distinct j1 from 
(select a.job_id as j1,b.job_id as j2 from paper1 a,paper2 b where a.job_id=b.job_id(+)) 
where j2 is null)