2010-08-11 102 views
1

我有一个带有2个表的SQL Server 2008数据库。这些表是地址和存储。这些表被定义为查找与SQL有关的记录

Address 
-------- 
ID (int) 
Line1 (nvarchar(255)) 
PostalCode (nvarchar(5)) 
City (nvarchar(255)) 
State (nvarchar(255)) 

Store 
----- 
ID (int) 
LocationID (int) 
Name 

我试图通过Line1和PostalCode找到位于相同地址的商店列表。由于重复的记录,我需要忽略ID。我不关心在他们所在地唯一的商店。相反,我只想要一个共享位置的商店列表。不幸的是,我不知道如何做到这一点。

如何编写一个查询,该查询只返回在相同的Line1和PostalCode中组地址的记录?

谢谢!

回答

2
select s.ID, s.LocationID, s.Name, a.ID, a.Line1, a.PostalCode 
from (
    select Line1 + ', ' + PostalCode as Line1PostalCode 
    from Address a 
    inner join Store s on a.ID = s.LocationID 
    group by Line1+ ', ' + PostalCode 
    having count(*) > 1 
) ag 
inner join Address a on ag.Line1PostalCode = a.Line1+ ', ' + a.PostalCode 
inner join Store s on a.ID = s.LocationID 
+0

HAVING!我总是忘记HAVING功能。谢谢。 – user336786 2010-08-11 14:06:53

3

这是你想要的吗?

SELECT t1.*, s.* FROM 
(SELECT Line1 ,PostalCode 
FROM Address 
GROUP BY Line1 ,PostalCode 
HAVING COUNT(*) >1) t2 
JOIN Address t1 ON t2.Line1 = t2.Line1 
AND t1.PostalCode = t2.PostalCode 
JOIN Store s on t1.ID = s.LocationID 
0

此查询使用子查询来查找具有多个商店的所有地址,然后将其用作选择要显示的商店的基础。

WITH StoreAddress AS 
(
SELECT * FROM Store s INNER JOIN Address a ON s.LocationID=a.LocationID 
) 
SELECT sa.* FROM StoreAddress sa INNER JOIN 
    (SELECT Line1, PostCode FROM StoreAddress 
    GROUP BY Line1, PostCode 
    HAVING Count(ID)>1) pairs 
ON pairs.Line1=sa.Line1 AND pairs.PostCode=sa.PostCode 
ORDER BY sa.Line1, sa.PostCode 

查询按Line1和PostCode排序,以便同一位置的商店一起显示。