问: DBL_MIN是最小正双倍吗?DBL_MIN是最小的正数倍吗?
下面的代码似乎用no来解释这个问题。但是,如果这是真的,DBL_MIN如何定义以及它的用途或目的是什么。
平台:Windows7的&的Visual Studio 2013
double next_to_zero = std::nextafter(0.0,DBL_MIN);
bool b = DBL_MIN <= next_to_zero;
std::cout << std::boolalpha
<< "is dbl_min the smallest representable double? "
<< b << '\n';
std::cout << std::setprecision(56)
<< "dbl_min = " << DBL_MIN << '\n'
<< "next to zero = " << next_to_zero;
输出:
是DBL_MIN表示的最小双?假
DBL_MIN = 2.2250738585072013830902327173324040642192159804623318306e-308
接零= 4.9406564584124654417656879286822137236505980261432476443e-324
C++的std :: numeric_limits ::分钟文档:http://en.cppreference.com/w/cpp/types/numeric_limits/min –