嵌套列表理解

Question

我有2个表，A和B.

• A是包含值的列表词典列表。
• B是一个简单的列表。

要求是列表B的元素添加到A.

下面是代码的字典中的值，

a = [{'a':[1,5]}, {'b' : [6,10]}, {'c' : [11,15]}] 
b = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15] 

for i in a: 
    for k,j in i.items(): 
     for m,n in enumerate(b): 
      if j[0]<= n<=j[1]: 
       j.append(n) 

print(a) 

[{'a':[1,5,1,2,3,4,5]}, {'b' : [6,10,6,7,8,9,10]}, {'c' : 
[11,15,11,12,13,14,15]}] 

# tried list comprehension 
a= [{k:n} for i in a for k,j in i.items() for m,n in enumerate(b) 
if j[0]<= n<=j[1]] 

print(a) 

[{'a': 1}, {'a': 2}, {'a': 3}, {'a': 4}, {'a': 5}, {'b': 6}, {'b': 7}, 
{'b': 8}, {'b': 9}, {'b': 10}, {'c': 11}, {'c': 12}, {'c': 13}, {'c': 
14}, {'c': 15}] 

问题是，这是否可以使用列表理解来完成？我尝试过但无法生成所需的输出。

Answer 1

a = [{k: [ x for x in b if v[0] <= x <= v[1] ]} for d in a for k,v in d.items()] 

Answer 2

只需对@Błotosmętek答案进行小修改即可获得您需要的输出结果。

a = [{'a': [1, 5]}, {'b': [6, 10]}, {'c': [11, 15]}] 
b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15] 

a = [{k: v+[x for x in b if v[0]<=x<=v[1]]} for d in a for k, v in d.items()] 
print(a) 

---

输出

[{'a': [1, 5, 1, 2, 3, 4, 5]}, {'b': [6, 10, 6, 7, 8, 9, 10]}, {'c': [11, 15, 11, 12, 13, 14, 15]}]