1
返回新对象,我有以下方法:嘲弄与andReturn
public function getThreads()
{
$results = \DB::select(\DB::raw(config('sql.messages.threads')), [$this->user->user_id]);
$messagesThreadsModel = app()->make(MessagesThreadsModel::class);
$messages = [];
foreach ($results as $r) {
$message = $messagesThreadsModel->find($r->messages_thread_id);
$message->unread = $r->unread;
$messages[] = $message;
}
return $messages;
}
为了测试上面我嘲笑通话\ DB ::选择(通过Laravel的门面)返回的对象列表如本数据库类通常做。然后加载消息线程模型,该模型在容器中被再次模拟并替换(因此app() - > make()将返回它的模拟实例,而不是实际模型)。
最后这一点:
$messagesThreadsModel->find($r->messages_thread_id);
再次嘲笑返回一个虚拟对象(存根?)。全部如下:
$threadsList = $this->mockThreads();
// mock the raw expression, check the query
\DB::shouldReceive('raw')->once()->with(m::on(function($sql)
{
return strpos($sql, 'messages') !== false;
}))->andReturn(true);
// mock the DB call, return a list of objects
\DB::shouldReceive('select')->once()->with(true, [$this->usersModel->user_id, $this->usersModel->user_id, $this->usersModel->user_id])->andReturn($threadsList);
$mockThreadResult = new \StdClass;
$mockThreadResult->last = "date";
$this->messagesThreadModel->makePartial();
// HERE IS THE TRICKY PART!
$this->messagesThreadModel->shouldReceive('find')->times(count($threadsList))->andReturn($mockThreadResult);
$this->app->instance('App\Freemiom\Models\Messages\MessagesThreads', $this->messagesThreadModel);
$messages = new Messages($this->usersModel);
$threadList = $messages->getThreads();
现在是什么问题?因为我传递了已创建的虚拟对象,每次在循环中调用 - > find方法时,都会返回相同的对象。
我应该如何告诉嘲笑每次调用返回一个新的对象?它甚至有可能吗?或者,也许我应该做一些代码重构,使其全部可测试?