从数组更改下拉框到复选框

Question

我想从下拉菜单中选择一个复选框，我想更改它，因为我希望首先选择数组中的列表，然后可以通过复选框将数据存储到数据库之前选中下拉脚本如下

<?php 
session_start(); 
define('DEFAULT_SOURCE','Site_A'); 
define('DEFAULT_VALUE',100); 
define('DEFAULT_STC','BGS'); 
include('class/stockconvert_class.php'); 
$st = new st_exchange_conv(DEFAULT_SOURCE); 
if(isset($_GET['reset'])) { 
    unset($_SESSION['selected']); 
    header("Location: ".basename($_SERVER['PHP_SELF'])); 
    exit(); 
} 
?> 
<form action="do.php" method="post"> 
<label for="amount">Amount:</label> 
<input type="input" name="amount" id="amount" value="1"> 
<select name="from"> 
<?php 
$stocks = $st->stocks(); 
asort($stocks); 
foreach($stocks as $key=>$stock) 
{ 
    if((isset($_SESSION['selected']) && strcmp($_SESSION['selected'],$key) == 0) || (!isset($_SESSION['selected']) && strcmp(DEFAULT_STC,$key) == 0)) 
    { 
    ?> 
    <option value="<?php echo $key; ?>" selected="selected"><?php echo $stock; ?></option> 
    <?php 
    } 
    else 
    { 
    ?> 
    <option value="<?php echo $key; ?>"><?php echo $stock; ?></option> 
    <?php 
    } 
} 
?> 
</select> 
<input type="submit" name="submit" value="Convert"> 
</form> 

和我改成复选框如下

<?php 
session_start(); 
define('DEFAULT_SOURCE','Site_A'); 
define('DEFAULT_VALUE',100); 
define('DEFAULT_STC','BGS'); 
include('class/stockconvert_class.php'); 
$st = new st_exchange_conv(DEFAULT_SOURCE); 
if(isset($_GET['reset'])) { 
    unset($_SESSION['selected']); 
    header("Location: ".basename($_SERVER['PHP_SELF'])); 
    exit(); 
} 
?> 
<form action="do.php" method="post"> 
<label for="amount">Amount:</label> 
<input type="input" name="amount" id="amount" value="1"><input type="submit" name="submit" value="Convert"> 
<?php 
$stocks = $st->stocks(); 
asort($stocks); 
foreach($stocks as $key=>$stock) 
{ 
    if((isset($_SESSION['selected']) && strcmp($_SESSION['selected'],$key) == 0) || (!isset($_SESSION['selected']) && strcmp(DEFAULT_STC,$key) == 0)) 
    { 
    ?> 
    <br><input type="checkbox" id="scb1" name="from[]" value="<?php echo $key; ?>" checked="checked"><?php echo $stock; ?> 
    <?php 
    } 
    else 
    { 
    ?> 
    <br><input type="checkbox" id="scb1" name="from[]" value="<?php echo $key; ?>"><?php echo $stock; ?> 
    <?php 
    } 
} 
?> 
</form> 

但不工作，我是否需要显示其他相关的代码？

感谢，如果有人帮助，感激

更新： 确定后第一显然是不太明显的，所以我会添加错误

的问题的错误是 致命错误：调用未定义的方法st_exchange_conv ::用C转换（）：\ XAMPP \ htdocs中\上线路测试\ do.php 21

线21是$st->convert($from,$key,$date);

session_start(); 
if(isset($_POST['submit'])) 
{ 
    include('class/stockconvert_class.php'); 
    $st = new st_exchange_conv(DEFAULT_SOURCE); 
    $from = mysql_real_escape_string(stripslashes($_POST['from'])); 
    $value = floatval($_POST['amount']); 
    $date = date('Y-m-d H:i:s'); 
    $_SESSION['selected'] = $from; 
    $stocks = $st->stocks(); 
    asort($stocks); 

    foreach($stocks as $key=>$stock) 
    { 
     $st->convert($from,$key,$date); 
     $stc_price = $st->price($value); 
     $stock = mysql_real_escape_string(stripslashes($stock)); 
     $count = "SELECT * FROM oc_stock WHERE stock = '$key'"; 
     $result = mysql_query($count) or die(mysql_error()); 
     $sql = ''; 
     if(mysql_num_rows($result) == 1) 
     { 
      $sql = "UPDATE oc_stock SET stock_title = '$stock', stc_val = '$stc_price', date_updated = '$date' WHERE stock = '$key'"; 
     } 
     else 
     {  
     $sql = "INSERT INTO oc_stock(stock_id,stock_title,stock,decimal_place,stc_val,date_updated) VALUES ('','$stock','$key','2',$stc_price,'$date')"; 
     } 
     $result = mysql_query($sql) or die(mysql_error().'<br />'.$sql); 
    } 
    header("Location: index.php"); 
    exit(); 
} 

为什么我要将其从下拉菜单更改为复选框？ 因为通过复选框列表我将能够选择哪些我检查它是数据库的入口，那么它对我来说似乎并不简单，我寻求一些帮助<谢谢这么多对于你的队友。

Answer 1

您还没有删除开头<select>标记。

但您删除了<submit>按钮。

您将name从“from”更改为“from [from]”。

编辑：你的补充后：

使用你只能选择一个from值的下拉列表。现在您将其更改为复选框，从而可以选择多个条目。这会导致在do.php的脚本中收到一个数组from[]。您的功能无法以任何方式处理数组或多个选择。

您必须重新设计do.php，将表单更改回下拉列表或使用比率按钮。