Makefile：用于比较的测试makefile

我需要生成一个makefile，它将我的写入命令grep输出与.out文件进行比较。 grep搜索的输入文本文件在tests/*。test中。Makefile：用于比较的测试makefile

贝塔的回答是非常有益的，但我不明白为什么使用make makefile all -n

make: Nothing to be done for `makefile'. 
echo tests/%.test 
echo outputs/%.out 
./grep apple tests/%.test >STDOUT diff STDOUT outputs/.out > 1.diff 
./grep apple tests/%.test >STDOUT diff STDOUT outputs/.out > 2.diff 
./grep apple tests/%.test >STDOUT diff STDOUT outputs/.out > 3.diff 
echo tests/1.test tests/2.test tests/3.test 
echo 1.diff 2.diff 3.diff

与此生成的文件

INPUT_DIR=tests 

OUTPUT_DIR=outputs 

FILES=$(wildcard ${INPUT_DIR}/*.test) 

TEST_LIST = ${FILES:${INPUT_DIR}/%.test=%.diff} 

.PHONY: all clean distclean 

all: ${TEST_LIST} 
    echo ${FILES} 
    echo ${TEST_LIST} 
${TEST_LIST}: ${INPUT_DIR}/%.test ${OUTPUT_DIR}/%.out 
    ./grep apple $< >STDOUT 
    diff STDOUT ${OUTPUT_DIR}/$*.out > [email protected] 
${INPUT_DIR}/%.test: 
    echo [email protected] 
${OUTPUT_DIR}/%.out: 
    echo [email protected] 
clean: 
    rm -f ${FILES}

使用make makefile all

make: Nothing to be done for `makefile'. 
echo tests/%.test tests/%.test 
echo outputs/%.out outputs/%.out 
./grep apple tests/%.test >STDOUT

来源

2012-12-07 Mantas Marcinkus

我不确定你的问题是什么（或者你究竟想要做什么），但是你所有的规则几乎肯定不会做你想要的。 – Beta

你的问题还不清楚，但由于你使用文件STDOUT作为中间文件，并使用它为每一个对比，你用它来没有别的，我劝你还是规则结合起来：

%.diff: ${INPUT_DIR}/%.test ${OUTPUT_DIR}/%.out 
    ./grep apple $< >STDOUT # Do you really have an executable called "grep"? 
    diff STDOUT ${OUTPUT_DIR}/$*.out > [email protected]

此外，您all规则不会做你期望的。试试这个：

all: 
    @echo you must specify a target, e.g. outputs/foo.diff

来源

2012-12-07 19:53:29 Beta

Makefile：用于比较的测试makefile

回答

相关问题