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这里的功能:传递一个mysql连接到功能
function getCount($module, $db_link) {
if($module == "tweets") {
$query = "SELECT COUNT(*) FROM tweets WHERE `read`='n'";
$tweet_count = mysqli_query($db_link,$query);
echo $tweet_count;
}
}
这里的链接(这是在代码前面定义):
$mysqli = mysqli_connect("localhost", "twitterd", "password", "twitterd") or die('Cannot connect to the database');
函数调用:
<?php getCount("tweets", $mysqli); ?>
如何将$mysqli
链接传递给getCount函数?目前,我得到这个错误:
Catchable fatal error: Object of class mysqli_result could not be converted to string in lib.php on line 7
这是什么问题? – 2012-07-21 04:52:24