如何从数据库Mysql中选择数据并将其添加到DataGridView上？

Question

这样做的目的是为了防止您加载了数据并且想要使用textbox来搜索人的姓名，电话号码等并键入他的姓名，它将通过单击按钮直接添加到空数据网格视图中。

string box = txtSearch.Text; 
      string table = "reservations"; 
      string query = "SELECT FROM reservations WHERE Client like '%" + box; 
      connection.Open(); 
      MySqlDataAdapter da_res = null; 
      DataSet ds_res = null; 
      ds_res = new DataSet(); 
      da_res = new MySqlDataAdapter(query, connection); 
      da_res.Fill(ds_res, table); 

      dgvUser.DataSource = ds_res.Tables[table]; 

这里的代码实际上我有6个colums我只尝试过一个到目前为止。该erorr发生在da_res.Fill(ds_res, table);

这是erorr细节：

您的SQL语法错误;检查对应于你的MySQL服务器版本在第1" 行

MySqlConnection connection = null; 
      string hostname = "localhost"; 
      string database = "aparece_hoteldb"; 
      string username = "root"; 
      string password = ""; 
      connection = new MySqlConnection("host=" + hostname + 
              ";database=" + database + 
              ";username=" + username + 
              ";password=" + password + ";"); 

Answer 1

恰克这个“FROM保留WHERE客户LIKE'％名客户的使用附近的正确语法手册：

string query = "SELECT FROM reservations WHERE Client like '%" + box; 

到这：

string query = "SELECT * FROM reservations WHERE Client like '%" + box +"%'"; 

您不选择任何列

，当你问她。 e是对你工作示例（你真的需要学习使用谷歌）...

private void MainClass_Load(object sender, System.EventArgs e) 
{ 
    string connectionString = @"Driver={MySQL};SERVER=localhost;DATABASE=NorthwindMySQL;"; 

    OdbcConnection conn= new OdbcConnection(connectionString); 
    conn.Open(); 

    OdbcDataAdapter da = new OdbcDataAdapter ("SELECT CustomerID, ContactName, ContactTitle FROM Customers", conn);    

    DataSet ds = new DataSet("Cust");  
    da.Fill(ds, "Customers"); 

    dataGrid1.DataSource = ds.DefaultViewManager; 
    conn.Close(); 
}