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我有一个非常简单的Spring MVC项目:如何在春天MVC结果页上的URL参数?
@Controller
@RequestMapping("/form.htm")
public class FormController {
FormValidation formValidation;
@Autowired
public FormController(FormValidation formValidation) {
this.formValidation = formValidation;
}
@RequestMapping(method = RequestMethod.GET)
public String initForm(ModelMap model) {
QueryForm queryForm = new QueryForm();
model.addAttribute("queryForm", queryForm);
return "queryForm";
}
@RequestMapping(method = RequestMethod.POST)
public String submitForm(ModelMap model, @ModelAttribute("queryForm")QueryForm queryForm,
BindingResult result) {
List<String> Result = query(queryForm);
SuccessForm successForm = new SuccessForm();
successForm.setId(queryForm.getId());
model.addAttribute("successForm", successForm);
return "successForm";
}
private List<String> query(QueryForm queryForm) {
}
}
的success.jsp:
<head>
<title>deviceInfo display</title>
</head>
<body>
<h1>Id is ${successForm.Id}.</h1>
<br>
<c:forEach var="info" items="${successForm.Info}" >
<p style="font-size:120%"><c:out value="${info}" /></p>
<hr />
</c:forEach>
<br>
</body>
</html>
query.jsp:
<head>
<meta charset="utf-8">
</head>
<body>
<div id="main">
<form class="form" id="queryForm" method="POST" command="queryForm">
<fieldset>
<legend>Please fill in the form</legend>
<p>
<label for="Id" class="sr-only">Id</label>
<input type="text" name="Id" id="Id" class="form-control" placeholder="Id">
</p>
<p>
<button class="btn btn-lg btn-primary btn-block" type="submit">Submit</button>
</p>
</fieldset>
</form>
</div>
</body>
</html>
这样
,成功的网址。 jsp页面与query.jsp相同:http://localhost:8080/project/form.htm。我需要在query.jsp上添加一些参数,如:http://localhost:8080/project/form.htm?Id=xxx,所以成功页面可以发送给其他人,结果存在,我该怎么做?谢谢。
Spring MVC的版本:2.5.6
谢谢,我可以访问successForm中的属性,但我怎样才能使用它们来生成URL的参数? – nzomkxia