我从主要活动携带产品ID到详细活动,然后进行评论活动。我正在使用Volley和Android Studio。我有一个从远程数据库填充的列表视图。当一个项目被点击时,这些项目的id将通过一个意图传递给该细节活动。在详细的活动中,当用户点击FAB时,该产品ID也会使用意图传递给评论活动。当我点击FAB时,评论活动打开但没有显示任何内容。我的Android Studio中的logcat,我收到以下错误:错误尝试POST指定的“ID”到服务器的JSON响应与Android Volley
Comments: Error: org.json.JSONException: Value <br of type java.lang.String cannot be converted to JSONArray
这是检索指定产品ID注释的PHP代码:
<?php
include_once("config.php");
$query=mysqli_query($con,"SELECT * FROM comments WHERE pid=".$_GET['pid']);
$array;
while($result=mysqli_fetch_assoc($query)){
$array[]=$result;
}
echo json_encode($array);
?>
详细活动
FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.commentsfab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
//Pass the image title and url to DetailsActivity
Intent intentTwo = new Intent(ProductsDetail.this, Comments.class);
intentTwo.putExtra("pid", pid);
intentTwo.putExtra("name", name);
intentTwo.putExtra("image", img);
intentTwo.putExtra("rating", rating);
//Start comments activity
startActivity(intentTwo);
}
});
评论动态
public class Comments extends AppCompatActivity {
private ProgressDialog dialog=null ;
private NetworkImageView cmntImg;
private TextView cmtjjTxt;
private RatingBar cmntRB;
private String TAG="Comments";
private String tag_json_arry = "json_array_req";
private String url = "http://192.168.0.5:80/demoapp";
private String url_file="/comments.php";
private CommentsAdapter adapter;
private ListView list;
ArrayList<CommentsRowData> cmntrowdata;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.comments);
final String pid = getIntent().getStringExtra("pid");
final String name = getIntent().getStringExtra("name");
final String img = getIntent().getStringExtra("image");
final String rating = getIntent().getStringExtra("rating");
list=(ListView)findViewById(R.id.commentsList);
cmntrowdata=new ArrayList<CommentsRowData>();
dialog= new ProgressDialog(this);
dialog.setMessage("Loading...");
dialog.show();
cmntImg = (NetworkImageView)findViewById(R.id.picComments);
cmntImg.setImageUrl(img, VolleyController.getInstance().getImageLoader());
cmtjjTxt = (TextView)findViewById(R.id.titleComments);
cmtjjTxt.setText(name);
cmntRB = (RatingBar)findViewById(R.id.ratingBar3);
cmntRB.setRating(Float.valueOf(rating));
JsonArrayRequest request = new JsonArrayRequest(url+url_file,
new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
Log.d(TAG, response.toString()); try {
for(int i=0;i<response.length();i++){
String pid=response.getJSONObject(i).getString("pid");
String cid=response.getJSONObject(i).getString("cid");
String username = response.getJSONObject(i).getString("username");
String comment = response.getJSONObject(i).getString("comment");
cmntrowdata.add(new CommentsRowData(pid,cid,username,comment));
}
} catch (JSONException e) {
e.printStackTrace();
}
adapter=new CommentsAdapter(Comments.this, cmntrowdata);
list.setAdapter(adapter);
dialog.dismiss();
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.d(TAG, "Error: " + error.getMessage());
dialog.dismiss();
}
//@Override
protected Map<String, String> getParams(){
Map<String,String> params = new HashMap<String,String>();
params.put("pid",pid);
return params;
}
});
VolleyController.getInstance().addToRequestQueue(request, tag_json_arry);
}
@Override
protected void onResume() {
super.onResume();
}
@Override
protected void onPause() {
super.onPause();
}
}
产品在一张表中,并且注释位于单独的表中。这就是为什么我要通过意图传递“pid”。我正在尝试仅针对与给定“pid”相对应的注释获取注释的JSON响应。 comments表看起来是这样的:
- PID(产品ID)
- CID(注释ID)
- 用户名
- 评论
编辑 如果我输入以下网址在我的浏览器中,
我得到以下JSON响应..
[
{
"pid": "2",
"cid": "1",
"username": "john",
"comment": "one of my favorites"
},
{
"pid": "2",
"cid": "2",
"username": "jane",
"comment": "this was so yummy"
}
]
因此,必须有我的Android代码中的东西,导致错误
我很抱歉,之前设置的内容类型的JSON在头
把
header('Content-Type: application/json');
在你的PHP文件,但我不明白你的意思。我不是那种先进的编程。你能再解释一下吗? –这意味着你在响应人身上有html标签,比如'
',这在json中是不可接受的 –
那么我该如何解决这个问题呢?或者,如何找到不需要的标签? –