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我想从两个不同表(TABLE_A和TABLE_B)中选择行。我使用的是oracle db和hibernate。这里是我的表:SQL从具有不同列名的两个不同表中选择行
下面是TABLE_A
+----+--------+---------+-----------+---------------------+---------------------+
| ID | AMOUNT | BALANCE | STATUS | CREATE_DATE | END_DATE |
+----+--------+---------+-----------+---------------------+---------------------+
| 1 | 5 | 5 | FINISHED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 2 | 12 | 17 | TIMED_OUT | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 3 | 21 | 38 | COMMITED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
+----+--------+---------+-----------+---------------------+---------------------+
下面是TABLE_B
+----+----------------+---------------+----------------+---------------------+
| ID | PAYMENT_AMOUNT | TOTAL_BALANCE | PAYMENT_STATUS | REQUEST_TIMESTAMP |
+----+----------------+---------------+----------------+---------------------+
| 1 | 3 | 23 | FAILED | 2014-02-27 15:10:20 |
| 2 | 12 | 11 | FULFILLED | 2014-02-27 15:10:20 |
| 3 | 2 | 9 | TIMED_OUT | 2014-02-27 15:10:20 |
+----+----------------+---------------+----------------+---------------------+
我想要做的是,我需要得到像单个查询以下结果:
+--------+---------+-----------+---------------------+---------------------+
| AMOUNT | BALANCE | STATUS | DATE | END_DATE |
+--------+---------+-----------+---------------------+---------------------+
| 5 | 5 | FINISHED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 12 | 17 | TIMED_OUT | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 21 | 38 | COMMITED | 2014-02-27 15:10:20 | 2014-02-27 15:10:20 |
| 3 | 23 | FAILED | 2014-02-27 15:10:20 | null |
| 12 | 11 | FULFILLED | 2014-02-27 15:10:20 | null |
| 2 | 9 | TIMED_OUT | 2014-02-27 15:10:20 | null |
+--------+---------+-----------+---------------------+---------------------+
的结果是ordered by DATE
。列的说明如下:
AMOUNT = TABLE_A.AMOUNT or TABLE_B.PAYMENT_AMOUNT
BALANCE = TABLE_A.BALANCe or TABLE_B.TOTAL_BALANCE
STATUS = TABLE_A.STATUS or TABLE_B.PAYMENT_STATUS
DATE = TABLE_A.CREATE_DATE or TABLE_B.REQUEST_TIMESTAMP
END_DATE = TABLE_A.END_DATE or null
有没有什么办法让这些类型的Oracle数据库中,并结合这些结果以Java中的Hibernate对象的任何方式的结果呢?
谢谢,我发现'UNION ALL'和它的工作对我来说:) – sedran