我需要遍历.mainheader
类.mainheader
,因为我需要header
类行和分组获取从一个类元素,在HTML表另一个类
这values
类行值是我的HTML
<table id="t01" cellspacing="0" cellpadding="0" class="table" style="margin-top:20px">
<thead>
<tr>
<th class="sorting">Group_Main_ID</th>
<th class="sorting">Group_Sub_ID</th>
<th class="sorting">Item</th>
<th class="sorting">Instructions</th>
<th class="sorting">Decision_Request_Input</th>
<th class="sorting">Status</th>
<th class="sorting">Evidence_Info</th>
<th class="sorting">Evidence_Doc</th>
</tr>
</thead>
<tfoot></tfoot>
<tbody id="editContents">
<tr id="1" class="mainheader " bgcolor="#000033">
<td id="nonEdit" class="th1 p_no" bgcolor="#215F8B">
<font color="white" align="left"></font>
</td>
<td class="th" bgcolor="#215F8B" align="left" style="color: white; display: table-cell;" colspan="7">
<font color="white" align="left"></font>
Header1</td>
</tr>
<tr id="2" class="header " bgcolor="#000033" style="opacity:0.8">
<td id="nonEdit" class="th1" bgcolor="#215F8B">
<font color="white" align="left"></font>
</td>
<td class="th" bgcolor="#215F8B" align="left" style="color: white; display: table-cell;" colspan="7">
<font color="white" align="left"></font>
SubHeader1</td>
</tr>
<tr class="values">
<td class="sno">1</td>
<td>1</td>
<td>4</td>
<td>1</td>
<td>2</td>
<td>1</td>
<td>null</td>
<td>Yes#No#NA</td>
</tr>
<tr class="values">
<td class="sno">1</td>
<td>1</td>
<td>4</td>
<td>1</td>
<td>2</td>
<td>1</td>
<td>null</td>
<td>Yes#No#NA</td>
</tr>
<tr class="values">
<td class="sno">1</td>
<td>1</td>
<td>4</td>
<td>1</td>
<td>2</td>
<td>1</td>
<td>null</td>
<td>Yes#No#NA</td>
</tr>
<tr id="2" class="header " bgcolor="#000033" style="opacity:0.8">
<td id="nonEdit" class="th1" bgcolor="#215F8B">
<font color="white" align="left"></font>
</td>
<td class="th" bgcolor="#215F8B" align="left" style="color: white; display: table-cell;" colspan="7">
<font color="white" align="left"></font>
Header1.2</td>
</tr>
<tr class="values">
<td class="sno">1</td>
<td>1</td>
<td>4</td>
<td>1</td>
<td>2</td>
<td>1</td>
<td>null</td>
<td>Yes#No#NA</td>
</tr>
<tr id="1" class="mainheader " bgcolor="#000033">
<td id="nonEdit" class="th1 p_no" bgcolor="#215F8B">
<font color="white" align="left"></font>
</td>
<td class="th" bgcolor="#215F8B" align="left" style="color: white; display: table-cell;" colspan="7">
<font color="white" align="left"></font>
Header2</td>
</tr>
<tr id="2" class="header " bgcolor="#000033" style="opacity:0.8">
<td id="nonEdit" class="th1" bgcolor="#215F8B">
<font color="white" align="left"></font>
</td>
<td class="th" bgcolor="#215F8B" align="left" style="color: white; display: table-cell;" colspan="7">
<font color="white" align="left"></font>
SubHeader2.1</td>
</tr>
<tr class="values">
<td class="sno">1</td>
<td>1</td>
<td>4</td>
<td>1</td>
<td>2</td>
<td>1</td>
<td>null</td>
<td>Yes#No#NA</td>
</tr>
</tbody>
</table>
我的JavaScript
var groupData = {};
var subGroupData = {};
var arr = [];
$('#t01 tbody tr.mainheader').each(function(i) {
var groupIdData ={};
groupIdData['id'] = $(this).attr('id');
groupIdData['name'] = $(this).find('td:eq(2)').text().trim()
groupIdData["action"]= 'Add/Edit/Delete'
//arr.push(garr)
groupData['group'] = groupIdData;
groupData['subgrps'] = [];
subGroupData = {};
subGroupData["action"]= 'Add/Edit/Delete'
subGroupData['id'] =$(this).next('.header').attr('id');
subGroupData['name']= $(this).next('.header').find('td:eq(2)').text().trim();
//arr.push(garr)
groupData['subgrps'].push(subGroupData)
subGroupData['items'] = [];
var items = [];
$(this).next('tr').each(function(){
if($(this).hasClass('values'))
{
var rowData = {};
$(this).find('td').each(function(i) {
var thh = $(this).closest('table').find('th').eq($(this).index()).text();
if(i == 0)
rowData["Action"]='Add/Edit/Delete'
if(i>1)
rowData[thh]=$(this).text().trim()
});
//arr.push(garr)
items.push(rowData)
}
else
return
});
//console.log('over')
}
subGroupData['items'].push(items);
groupData['subgrps'].push(subGroupData);
arr.push(groupData);
});
alert(JSON.stringify(arr)) ;
我的小提琴
https://jsfiddle.net/694kjj3o/
我期待JSON这个样子的
[
{
"group": {
"value": "Header1"
},
"subgrps": [
{
"name": {
"value": "SubHeader1.1"
},
"items": [
[
{
"value": {
"Group_Main_ID": 1,
"Group_Sub_ID": 5,
"Item": "4",
"Instructions": null,
"Decision_Request_Input": null,
"Status": null,
"Evidence_Info": null,
"Evidence_Doc": null
}
}
],
[
{
"value": {
"Group_Main_ID": 1,
"Group_Sub_ID": 5,
"Item": "4",
"Instructions": null,
"Decision_Request_Input": null,
"Status": null,
"Evidence_Info": null,
"Evidence_Doc": null
}
}
]
]
},
{
"name": {
"value": "SubHeader1.2"
},
"items": [
[
{
"value": {
"Group_Main_ID": 1,
"Group_Sub_ID": 5,
"Item": "4",
"Instructions": null,
"Decision_Request_Input": null,
"Status": null,
"Evidence_Info": null,
"Evidence_Doc": null
}
}
]
]
}
]
},
{
"group": {
"value": "Header2"
},
"subgrps": [
{
"name": {
"value": "Header2.1"
},
"items": [
[
{
"value": {
"Group_Main_ID": 1,
"Group_Sub_ID": 5,
"Item": "4",
"Instructions": null,
"Decision_Request_Input": null,
"Status": null,
"Evidence_Info": null,
"Evidence_Doc": null
}
}
]
]
}
]
}
]
我不能循环它。请在这种情况下指导我
更好地使用网络爬虫 – madalinivascu
我需要循环它并形成一个json,爬虫不会做表格json –
什么exacly不工作? – madalinivascu