sql从视图和表中选择

Question

我有一个选择查询，我想在视图和另一个表上进行联接。 视图工作正常，表格也是如此，单独。但是，当我尝试做一些事情，如：

select VIEW.col1, VIEW.col2 
from VIEW, TABLE 
where VIEW.col1 = TABLE.col1 

我得到The multi-part identifier "VIEW.col1" could not be bound.

是语法错误，或者是只是不允许的看法？

Answer 1

这应该工作

select v.col1, t.col2 
from VIEW v, TABLE t 
where v.col1 = t.col1 

Answer 2

SELECT VIEW.col1, VIEW.col2 
from VIEW AS VIEW INNER JOIN TABLE AS TABLE 
ON VIEW.col1 = TABLE.col1 

Answer 3

SELECT MYVIEWNAME.col1, MYVIEWNAME.col2 
FROM VIEWNAME AS MYVIEWNAME INNER JOIN TABLENAME AS MYTABLENAME 
ON MYVIEWNAME.col1 = MYTABLENAME.col1 

Answer 4

我建议你使用左或内部连接和别名表和视图。

select v.col1 , v.col2 

from view v 
inner join table t on t.col1 = v.col1 

Answer 5

你必须有view，如：

create table MyView 
as 
select column1 as col1, column2 as col2 
from tab 

or 

CREATE VIEW MyView (col1,col2) 
as 
select column1, column2 
from tab 

那么你可以用它加入：

select MyView.col1, MyView.col2 
from MyView, TABLE 
where MyView.col1 = MyView.col1 

or 

select v.col1, v.col2 
from MyView v, TABLE t 
where t.col1 = t.col1 

or 

select v.col1, v.col2 
from MyView v 
join TABLE t on t.col1 = t.col1 

也许一些例子将无法在所有的RDBMS工作。