为什么我打印3次输出？

当学生ID“sid”在搜索框中输入时，我需要从“stud”表中返回一些学生的详细信息。同样在第二部分中，我需要在我的数据库“enrl”中搜索注册表以获取此给定学生ID的注册课程的UCAS ID。为什么我打印3次输出？

问题是为什么我会搜索我的搜索的第二部分3次？这里是我的代码：

<?php 
mysql_connect("localhost","root","") or die ("Could Not Connect!"); 
mysql_select_db("swanseauniversity") or die ("Could Not Connect to   database!"); 

$output = ''; 
$output2 = ''; 
//Collect 
if(isset($_POST['search'])){ 
    $searchq = $_POST['search']; 

//Search "stud" table 
    $query = mysql_query("SELECT * FROM stud WHERE sid LIKE '$searchq'") or die("Could not Search"); 
    $count = mysql_num_rows($query); 
    if($count == 0){ 
     $output = 'there was no search result'; 
    } 
    else { 
     while($row = mysql_fetch_array($query)){ 
      $id = $row['sid']; 
      $title = $row['title']; 
      $fname = $row['firstname']; 
      $lname = $row['lastname']; 
      $DOB = $row['dob']; 
      if ($row['gender'] == 'f'){ 
       $gender = 'Female'; 
      } 
      if ($row['gender'] == 'm'){ 
       $gender = 'Male'; 
      } 

      $output .= 
      '<table style="width:100%", frame="box">' 
       .'<tr>' 
        .'<td>'.'Student ID'.'</td>' 
        .'<td>'. $id.'</td>' 
       .'</tr>' 
       .'<tr>' 
        .'<td>'.'Title'.'</td>' 
        .'<td>'. $title.'</td>' 
       .'</tr>' 
       .'<tr>' 
        .'<td>'.'Fullname:'.'</td>' 
        .'<td>'. $fname.' '.$lname.'</td>' 
       .'</tr>' 
       .'<tr>' 
        .'<td>'.'Date of Birth:'.'</td>' 
        .'<td>'. $DOB.'</td>' 
       .'</tr>' 
       .'<tr>' 
        .'<td>'.'Gender'.'</td>' 
        .'<td>'. $gender.'</td>' 
       .'</tr>' 
      .'</table>' 

      ; 
     } 
    } 


    //Search "enrl" Table 
    $query = mysql_query("SELECT * FROM enrl WHERE sid LIKE '$searchq'") or  die("Could not Search"); 
    $count = mysql_num_rows($query); 
    if($count == 0){ 
     $output2 = 'there was no search result'; 
    } 
    else { 
     while($row = mysql_fetch_array($query)){ 
      $enrolledcourse = $row['pid']; 

      $output2 .= 
      '<table style="width:100%", frame="box">' 
       .'<tr>' 
        .'<td>'.'UCAS Code'.'</td>' 
        .'<td>'. $enrolledcourse.'</td>' 
       .'</tr>' 
       .'<tr>' 
        .'<td>'.'dummy1'.'</td>' 
        .'<td>'. '</td>' 
       .'</tr>' 
       .'<tr>' 
        .'<td>'.'dummy2'.'</td>' 
        .'<td>'. '</td>' 
       .'</tr>' 
      .'</table>' 

      ; 
     } 
    } 
} 

?> 
<html> 
    <head> 
    <title>Student Search</title> 
    </head> 
    <body> 
<!--SEARCH FORM--> 
     <form action="index.php" method="post"> 
      <label>Query by Student ID #:</label> <input type="text"  name="search" placeholder="Search for students..."/> 
      <input type="submit" value="Submit"/> 
     </form> 

    <hr> 

    <h4 style="margin-bottom:0px">Personal Details</h4> 
    <?php 
    print("$output"); 
    ?> 

    <h4 style="margin-bottom:0px">Course Details</h4> 
    <?php 
    print("$output2"); 
    ?> 
    </body> 
</html>

RESULT

来源

2015-11-26 user3050565

你有三行数据相同吗？你的代码是按照SQL注入开放的。你应该更新到'PDO'或'mysqli'驱动程序。 – chris85

问题：

现在的问题是，为什么让我的搜索3倍的第二部分？

解决方案：

那是因为你不是寻找一个特定学生招生记录。

采取$id以外的所有块，像这样：

// your code 

$id = ''; 
if($count == 0){ 
    $output = 'there was no search result'; 
} 
else { 
    while($row = mysql_fetch_array($query)){ 
     $id = $row['sid']; 
     $title = $row['title']; 
     $fname = $row['firstname']; 
     $lname = $row['lastname']; 
     $DOB = $row['dob']; 
     if ($row['gender'] == 'f'){ 
      $gender = 'Female'; 
     } 
     if ($row['gender'] == 'm'){ 
      $gender = 'Male'; 
     } 

     // your code 
    } 

} 

// your code

，然后搜索enrl表对特别学生证，像这样：

//Search "enrl" Table 
$query = mysql_query("SELECT * FROM enrl WHERE sid = '$id'") or die("Could not Search"); 
// your code

旁注：请不要使用mysql_数据库扩展，它们在PHP 5.5.0中被弃用，并且在PHP 7.0.0中被删除。改为使用mysqli或PDO扩展名。这是why you shouldn't use mysql_ functions

来源

2015-11-26 00:47:42

非常欢迎！ :) –

为什么我打印3次输出？

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