当单击某个列表组时,我需要选择下一个(以下)列表组并将其更改为data-state = enabled .list-group,并将其删除类disabled
从每个列表组项选择下一个列表组并更改数据状态
我的代码越来越费解,我想知道 1)如何获取计数器工作,所以它不增加太多 抛出错误2)如何简化这个,而不使用jquery 3)如何使用jquery简化这个
<section>
<div class="list-group">
<h4>1. Select Doctor</h4>
<hr>
<a href="#" class="list-group-item active">Dr. Justice Freedom</a>
<a href="#" class="list-group-item">Dr. Martin Fabio</a>
<a href="#" class="list-group-item">Dr. Jenny Walter</a>
<a href="#" class="list-group-item">Dr. Loius Von Winkle</a>
<a href="#" class="list-group-item">Dr. Mary McDoctors</a>
<a href="#" class="list-group-item">Dr. Freethinker Liver</a>
<a href="#" class="list-group-item">Dr. Cognitive Thinker</a>
</div>
</section>
<section>
<div class="list-group" data-state="disabled">
<h4>2. Select Department</h4>
<hr>
<a href="#" class="list-group-item disabled">Cras justo odio</a>
<a href="#" class="list-group-item disabled active">Dapibus ac facilisis in</a>
<a href="#" class="list-group-item disabled">Morbi leo risus</a>
<a href="#" class="list-group-item disabled">Porta ac consectetur ac</a>
<a href="#" class="list-group-item disabled">Vestibulum at eros</a>
</div>
</section>
<section>
<div class="list-group" data-state="disabled">
<h4>3. Select Area</h4>
<hr>
<a href="#" class="list-group-item disabled active">Cras justo odio</a>
<a href="#" class="list-group-item disabled">Dapibus ac facilisis in</a>
<a href="#" class="list-group-item disabled">Morbi leo risus</a>
<a href="#" class="list-group-item disabled">Porta ac consectetur ac</a>
<a href="#" class="list-group-item disabled">Vestibulum at eros</a>
</div>
</section>
JS
var listGroup = document.querySelectorAll('#selectPatientCategories .list-group');
//console.log(listGroup);
var cats = document.querySelectorAll('a.list-group-item');
//console.log(cats);
var counter = 1;
// For each category list item
var catIndex = 0, catLength = cats.length;
for (; catIndex < catLength; catIndex++) {
var thiscat = cats[catIndex];
//console.log(listGroupIndex);
// Click function on list item
thiscat.addEventListener('click', function() {
//console.log(thisListGroup);
//Get the parent .list-group
thisListGroup = this.parentElement;
thisListGroupCats = thisListGroup.querySelectorAll('a.list-group-item');
//console.log(thisListGroupCats);
// For each category .list-group-item within this listGroup
var listGroupIndex = 0, listGroupCatsLength = thisListGroupCats.length;
for (; listGroupIndex < listGroupCatsLength; listGroupIndex++) {
// Focus on just this .list-group being iterated
rmThisCat = thisListGroupCats[listGroupIndex];
rmThisCat.classList.remove('active');
}
// Activate the clicked .list-group-item
this.classList.add('active');
// Activate the next list group
nextListGroup = listGroup[counter];
nextListGroup.setAttribute('data-state', 'enabled');
nextListGroupCats = nextListGroup.querySelectorAll('a.list-group-item');
nextCatIndex = 0;
console.log(nextListGroupCats);
for (; nextCatIndex < nextListGroupCats.length; nextCatIndex++) {
var nextCat = nextListGroupCats[nextCatIndex];
nextCat.classList.remove('disabled');
}
// increment the counter
counter++;
}); // End click function
}
您的需求2)如何简化这个不使用jQuery 3)如何使用jquery矛盾这个简化。你会愿意去适应一个jQuery版本吗? – DinoMyte
当然,我问这两个问题的原因是如果有人用javascript回答,我可以找出一个jQuery版本,反之亦然,所以我可以更好地学习。 Jquery版本对我来说很好。 – TetraDev