我想使用异步并等待,而我的问题是它不会等待后台进程完成。也许你想知道为什么我不能同步运行应用程序? 我想尽快完成我的任务的一部分,其余的可以等待,如本例中所示。 谢谢你们的帮助! =)如何知道使用异步时Task或Void方法是否仍在运行
class Program
{
static void Main(string[] args)
{
Run();
//Problem or Maybe Not? Needs this
//So that my application won't close immediately
Console.ReadLine();
}
private async static void Run()
{
Task<bool> TBool = ProcessRecords();
if (await TBool)
{
//Problem #1 This Line Doesn't Show
Console.WriteLine("End of Code");
//SHould be safe to close the application by Now
//But goes through here not waiting for the return
//of the last process.
Environment.Exit(0);
//My temporary solution is to indicate a Task.Delay(80000)
//to make sure that all the logging in the background
//are all done. I dont know if there is a function that shows
//that there are task running on the background or any
//other workaroung will help. =) thanks
}
}
private async static Task<bool> ProcessRecords()
{
Task newTask = null;
//Loop through all the records and send
//all the records to MQ ASAP
for (int x = 0; x < 10; x++)
{
//I wont wait for this Task so
//I can send the next record
newTask = SendToMQ(x);
}
//I only need to wait for the last Task to
//indicate that I can exit the system
//as soon as it finish
//Problem #2 The Console.WriteLine doesnt show the last record.
await newTask;
return true;
}
private async static Task SendToMQ(int count)
{
//actual sending of message (Important)
await Task.Delay(1000);
//Process of Logging Connect to DB etc, (Not so Important, but takes most of the time)
await LoggingRecord();
Console.Clear();
Console.WriteLine("Done Processing " + count.ToString() + " records");
}
//Logging of each record
private async static Task LoggingRecord()
{
await Task.Delay(5000);
//Problem #3 This Line Doesn't Show
Console.WriteLine("Last Log Finished");
}
}
你能不能设置一些布尔标志或分配和检查某些属性..?当你通过代码的时候会发生什么,最后的日志完成写入控制台主窗口..? – MethodMan
我编辑了你的标题。请参阅:“[应该在其标题中包含”标签“](http://meta.stackexchange.com/questions/19190/)”,其中的共识是“不,他们不应该”。 –
显然Logging没有完成他的事情,但应用程序强制关闭整个应用程序,即使Logging尚未完成写入,这就是为什么我给我的应用程序Task.Delay(8000)等待它登录,但这不仅仅是好的编码,也不是动态的。感谢所有的帮助=) –