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我想将PyQT4代码转换为PyQt5,它需要连接信号的新风格。 当我使用:PyQt5对话框关闭主窗口
self.connect(okButton, SIGNAL("clicked()"),form, SLOT("accept()"))
self.connect(cancelButton, SIGNAL("clicked()"),form, SLOT("reject()"))
一切正常 - 通过单击确定或取消,对话窗口将关闭。随着新的风格sygnals(其中我想我做错了什么)
okButton.clicked.connect(self.accept)
cancelButton.clicked.connect(self.reject)
点击确定后/取消,主窗口将关闭,对话框将保持。这绝对不是应该发生的事情。
我在做什么错?
import sys
from PyQt5.QtWidgets import QDialog, QApplication, QPushButton, QLabel, QHBoxLayout, QVBoxLayout, QGridLayout
# from PyQt4.QtCore import *
# from PyQt4.QtGui import *
class Form(QDialog):
def __init__(self, parent=None):
super(Form, self).__init__(parent)
myButton = QPushButton("open window")
self.myFirstLabel = QLabel("First Window")
layout = QVBoxLayout()
layout.addWidget(myButton)
layout.addWidget(self.myFirstLabel)
self.setLayout(layout)
myButton.clicked.connect(self.openNewWindow)
self.setWindowTitle("SecondWindowTest")
def openNewWindow(self):
myLabel = QLabel("Second Window")
okButton = QPushButton("&OK")
cancelButton = QPushButton("Cancel")
buttonLayout = QHBoxLayout()
buttonLayout.addStretch()
buttonLayout.addWidget(okButton)
buttonLayout.addWidget(cancelButton)
layout = QGridLayout()
layout.addWidget(myLabel, 0, 0)
layout.addLayout(buttonLayout, 1, 1, 1, 2)
form = QDialog()
form.setLayout(layout)
okButton.clicked.connect(self.accept)
cancelButton.clicked.connect(self.reject)
# self.connect(okButton, SIGNAL("clicked()"),form, SLOT("accept()"))
# self.connect(cancelButton, SIGNAL("clicked()"),form, SLOT("reject()"))
form.setWindowTitle("Second Window")
if form.exec_():
self.myFirstLabel.setText('OK was pressed')
app = QApplication(sys.argv)
form = Form()
form.show()
app.exec_()
什么您的问题或问题是什么? – eyllanesc
问题在于对话框关闭主窗口。为了清晰我已经编辑过主要内容 – tmdag