的Python如何打印包含数字

Question

字符串我有一个列表：

var = ["renderPass1", "renderPass2","renderPass3", "renderPassFilter", "renderPassSets"] 

我怎么只打印renderPass1，renederPass2等，我的意思是，以后只打印包含多个成员“renderPass”

Answer 1

使用正则表达式来查找数字。

检查python库：Python: Re。你会想看看“\ d”。

一个工具，可以帮助我很多正则表达式是Txt to Regex。你只需放入你想要匹配的字符串并用GUI构建正则表达式。然后它为您提供下面的代码。

Answer 2

根据您对列表中的内容知道多少选择一个。

打印头3

print var[:3] 

印刷与图案renderPass任何名称后跟数字

print [name for name in var if name.startswith('renderPass') and name[9].isdigit()] 

打印以数字任何名称的任意位置在它

print [name for name in var if any(ch.isdigit() for ch in name)] 

Answer 3

for value in var: 
    if value[-1].isdigit(): # check if last char is a number 
     print value 

现在如果y OU要测试的字符串“renderPass”

for value in var: 
     if 'renderPass' in value and value[-1].isdigit() 
      print value 

Answer 4

for name in var: 
    try: 
     float(name[len("renderPass"):]) 
     print name 
    except ValueError, er: 
     # does not have a number after renderPass -> do nothing 
     pass 

Answer 5

我给出两个答案，因为你的问题是没有什么被认为是匹配的太清楚。

这是因为如果该号码的位置是不相关：

>>> var = ["renderPass1", "renderPass2","renderPass3", "renderPassFilter", "renderPassSets"] 
>>> [x for x in var if any(c.isdigit() for c in x)] 
['renderPass1', 'renderPass2', 'renderPass3'] 
>>> 

这是因为如果该号码有"renderPass"后前来：

>>> from re import search 
>>> # I altered the values in here so I could demonstrate 
>>> var = ["renderPass1", "renderPass2","renderPass3", "1renderPassFilter", "1renderPassSets"] 
>>> [x for x in var if search("renderPass.*\d", x)] 
['renderPass1', 'renderPass2', 'renderPass3'] 
>>> 

Answer 6

假设你只需要与“SomeTextNumber”的模式，你可以这样写

[x for x in var if re.match("\w+\d$", x)] 

Answer 7

import re 
p = re.compile("[0-9]$") 
for s in var: 
    if p.search(s): print s