PowerShell：将每行CSV导出到单个文件

Question

我有一个制表符分隔的CSV，需要将每行分割为不同的CSV，文件名为[FirstName] [LastName] .csv。

此外，我需要操纵一些数据，特别是从SSN中删除破折号。

样本含量

FirstName LastName SSN 
========= ========= ====== 
Albert  Abernathy 111-11-1111 
Billy  Barty  222-22-2222 
Chris  Canton  333-33-3333 

所需的输出（文件名| CSV内容）

Albert Abernathy.csv | Albert  Abernathy 111111111 
Billy Barty.csv  | Billy  Barty  222222222 
Chris Canton.csv  | Chris  Canton  333333333 

这里是我到目前为止所。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
| Where-Object {$_.LastName -ne ""} ##Prevent importing blank lines 
| Foreach-Object {$_.SSN -Replace "-","" } ##Remove dashes from SSN 
foreach ($line in $csv) 
{ $saveName = $line.FirstName + " " + $line.LastName + ".csv" 
    Export-Csv -Delimiter "`t" -Path $folderPath\$saveName 
} 

到目前为止，所有这些都在运行，但它只是在最后一个条款之后暂停而没有任何反应。正如我拼凑在一起，这从谷歌搜索，我敢肯定，我的语法需要工作，所以我会很感激，如果有人能在正确的方向

--Update--

信用点我alroc将我指向正确的方向，mjolinor提供了无法在其他地方找到的无价REPLACE语法。这是我的最后脚本。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 

### filter out blank records and delete dashes from SSN ### 
(Get-Content $csvFile | 
    Select-Object | 
    Where-Object {$_.LastName -ne ""}) | #Rows with non-blank last name 
    Foreach-Object {$_ -Replace '(\d{3})-(\d{2})-(\d{4})','$1$2$3'} | 
    Set-Content $csvFile 

### import csv data and export file for each row ### 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
foreach ($row in $csv) { 
    $outPath = Join-Path -Path $folderPath -ChildPath $($row.FirstName + " " + $row.LastName + ".csv"); 
    $row | Select-Object | 
     ConvertTo-Csv -NoTypeInformation -Delimiter "`t" | 
     Foreach-Object {$_.Replace('"','')} | #Delete quotes around each "cell" 
     Out-File $outPath 
    (Get-Content $outPath | 
     Select-Object -Skip 1) | #Delete header 
     Set-Content $outPath 
} 

Answer 1

我不是你所说的“最后的条款后，只是停顿了一下，什么也没发生”，但它可能是与你的管路import-csv你的过程的其余部分，并试图指派清楚什么结果输入$csv。这个工作对我来说：

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
$csv = Import-Csv -Path $csvFile -Delimiter "`t" 
foreach ($record in $csv) { 
    $OutFileName = join-path -Path $folderPath -ChildPath $($record.FirstName + " " + $record.LastName + ".csv"); 
    $record|select-object FirstName,LastName,@{name="SSN";expression={$_.SSN -replace "-",""}}|export-csv -NoTypeInformation -Path $OutFileName -Delimiter "`t"; 
} 

或者，如果你想这样做，没有中间变量，保持更多的管道-Y：

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile 
Import-Csv -Path $csvFile -Delimiter "`t" | foreach { 
    $OutFileName = join-path -Path $folderPath -ChildPath $($_.FirstName + " " + $_.LastName + "2.csv"); 
    $_|select-object FirstName,LastName,@{name="SSN";expression={$_.SSN -replace "-",""}}|export-csv -NoTypeInformation -Path $OutFileName -Delimiter "`t"; 
} 

Answer 2

FWIW - 未经测试。保留尽可能多的原始脚本。

$csvFile = "C:\Test\List.csv" 
$folderPath = Split-Path -Parent $csvFile.fullname 

Import-Csv -Path $csvFile -Delimiter "`t" | 
Where-Object {$_.LastName -ne ""} | ##Prevent importing blank lines 
Foreach-Object { 
    $_.SSN = $_.SSN -Replace "-","" ##Remove dashes from SSN 
    $saveName = $_.FirstName + " " + $_.LastName + ".csv" 
    Export-Csv $_ -Delimiter "`t" -Path $folderPath\$saveName 
    }