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我开发了一个选择表单并使用ajax调用php脚本来获取结果,ajax正常工作并成功连接到了php,但是我无法获得php的结果无法获得结果表格php
这是我的表格:
<form method="post" action = "#">
<div class="functionitem" id="selector_phot">
<select name="photographer">
<option>All Photographers</option>
<option>John Baldwin</option>
<option>Wendy James</option>
<option>Ian Smith</option>
<option>Rebecca Fortesque-Smythe</option>
</select>
</div>
<div class="functionitem" id="selector_cat">
<select name="sets">
<option>All Sets</option>
<option>Ceremony</option>
<option>Lunch</option>
<option>Garden</option>
</select>
</div>
<div class="functionitem" id="viewresult"><span class="button"><span><input type="button" class="form_button" value=" View"></span></span>
</div>
<div class="functionitem" style="margin-right: 60px">
<span class="button"><span><input type="button" class="form_button" id="guestlogin" value=" Guest Login "></span></span>
</div>
<div class="functionitem">
<span class="button"><span><input type="button" class="form_button" id="register" value=" Register"></span></span>
</div>
这里是我的PHP脚本:
if(isset($_POST['photographer'])&&isset($_POST['sets']))
{
echo "results";
}
所以它应该打印出来的结果,但它没有做我做错了什么,请帮助,谢谢!
这里是ajax代码:
注意,为什么你的选项没有价值属性? –
你的ajax代码在哪里? –
似乎每一件事情都很好,发布你的ajax代码请 – confucius