2015-08-28 31 views
2
import scrapy 
from scrapy.spiders import CrawlSpider, Rule 
from scrapy.linkextractors import LinkExtractor 
from scrapy.selector import HtmlXPathSelector 
import os 
from Erowid.items import ErowidItem 
import codecs 

class ExperiencesSpider(CrawlSpider): 
    name = "experiences" 
    allowed_domains = ["www.erowid.org"] 
    start_urls = ['https://www.erowid.org/experiences/exp_list.shtml'] 
    rules = [ 
     Rule(LinkExtractor(allow =('subs/exp_[a-zA-Z]+.shtml')), follow = True), 
     Rule(LinkExtractor(allow=r'/experiences/exp\.php\?ID=\d+$'),callback='parse_item', follow = True) 
    ] 
    def parse_item(self, response): 
     selectors = response.css('div') 
     for selector in selectors: 
      experience = ErowidItem() 
      experience['Author'] = selector.xpath('//div[@class="author"]/a/text()').extract() 
      experience['Title'] = selector.xpath('//div[@class="title"]/text()').extract() 
      experience['Substance'] = selector.xpath('//div[@class="substance"]/text()').extract() 
      experience['Text'] = selector.xpath("//div[@class = 'report-text-surround']/text()").extract() 
      experience['Title'] = str(experience['Title']).replace('\\' , "") 
      experience['Title'] = str(experience['Title']).replace('?' , "") 

      directory = os.path.join('Erowid/archive/',experience['Substance'][0].strip().lower()) 
      filename = os.path.join(directory,experience['Title'][0]+'.txt') 

      if not os.path.exists(directory): 
       os.makedirs(directory) 

      with codecs.open(filename, encoding = 'utf-8', mode= 'wb') as fid: 
       for symbols in experience['Text']: 
        fid.write(symbols) 
     yield experience 

我试图刮Erowid,到目前为止,该代码是由这样我将创建一个目录,写主要基于文件经验的名称和文本。 (根据经验,我指的是我从Erowid处取消的信息。)Scrapy IO错误:[错误22]无效的模式(“WB”)或文件名

问题是,某些经验在其名称中包含不能写为文件的字符,因为它们包含的保留字符可以将不会在windows filenames中使用。

我试图消除所有这些保留的字符,这是

  • The following reserved characters:

    • < (less than)
    • > (greater than)
    • : (colon)
    • " (double quote)
    • / (forward slash)
    • \ (backslash)
    • | (vertical bar or pipe)
    • ? (question mark)
    • * (asterisk)

的我试图做一些与线

experience['Title'] = str(experience['Title']).replace('\\' , "") 
experience['Title'] = str(experience['Title']).replace('?' , "") 

(大多数错误来自“\”和“?”)但我仍然收到错误

IOError: [Errno 22] invalid mode ('wb') or filename: u'Erowid/archive/syrian rue\\Meditative Help?.txt' 

或其他一些我知道的文件名是wro因为不应该有问号或反斜杠。

我在做什么错误触发这些错误?

回答

2

您未能替换特殊字符。试试这个:

filename = os.path.join(directory,experience['Title'][0]+'.txt') 
filename = filename.replace('\\' , "").replace('?' , "") 

UPDATE

你只是想指定一个合法的文件名。所以我想出了一个这样的想法。

directory = os.path.join('Erowid/archive/',experience['Substance'][0].strip().lower()) 
filename = experience['Substance']+experience['Title'][0]+'.txt' 
filename = "".join([i for i in filename if i in string.ascii_letters]) 
#only use ascii letters as file name 
filename = os.path.join(directory, filename) 

string.ascii_letters

The concatenation of the ascii_lowercase and ascii_uppercase constants described below. This value is not locale-dependent.

+0

我认为这是一个,而答案,但,这是因为其中包含特殊字符是一个非常小的数目这样的文件的数量。 我仍然得到与文件命名不当有关的错误/变体。 –

+0

错误信息是什么?@DavidYi – luoluo

+0

IO错误:[Errno 22]无效模式('wb')或文件名: 与上面相同,但文件名不同 –

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