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这些链接为我点击时给出的每个结果给出了结果,但是如何显示所有'热''温暖'和'冷'线索,因为'全部'是默认页面?根据多个标准设置默认值
<li><a href="/dbs/a.php?contactstatus=">All</a></li>
<li><a href="/dbs/a.php?type=Appointment">Appointments</a></li>
<li><a href="/dbs/a.php?contactstatus=Hot">Hot</a></li>
<li><a href="/dbs/a.php?contactstatus=Warm">Warm</a></li>
<li><a href="/dbs/a.php?contactstatus=Cold">Cold</a></li>
if(isset($_GET['contactstatus'])
&& in_array($_GET['contactstatus'], array('Hot', 'Warm', 'Cold')))
{
$status = $_GET['contactstatus'];
$query = "SELECT * FROM contacts WHERE contactstatus = '".$status."' ORDER BY contacts.firstname ASC";
}
if(isset($_GET['type'])
&& in_array($_GET['type'], array('Appointment')))
{
$todotype = $_GET['type'];
$query = "SELECT * FROM contacts,contacttodo,contactnotes WHERE contacts.ID = contacttodo.contacts_id = contactnotes.contacts_id AND contacttodo.type = '".$todotype."' ORDER BY contacts.firstname ASC";
}
UPDATE:
得到这个通过增加工作:
$query = "SELECT * FROM contacts WHERE contactstatus = 'Hot' OR contactstatus = 'Warm' OR contactstatus = 'Cold' ORDER BY contacts.contacttype ASC";
然而,就是这样安全吗?
9个问题,15个回答没有意义?在继续之前接受一些答案。 –
@阿方索 - 你开心? – joshua76