基本上......当用户接受或拒绝好友请求时,它应该删除用户的名称,接受和拒绝按钮,但它只会删除用户的名称和拒绝按钮。我不明白。代码:C#我不明白为什么这个按钮不会删除
private void loadFriendRequests()
{
using (SqlConnection connection = new SqlConnection(con))
{
using (SqlCommand cmd = new SqlCommand(@"Select IDRequest, UserFirstName, UserLastName, FriendEmail From PendingRequests Where FriendEmail = @fe", connection))
{
connection.Open();
cmd.Parameters.AddWithValue("@fe", Properties.Settings.Default.Email);
using (SqlDataReader dr = cmd.ExecuteReader())
{
int i = 0;
while (dr.Read())
{
i++;
foreach (object request in i.ToString())
{
Label userName = new Label();
Button accept = new Button();
Button reject = new Button();
accept.Text = "Accept";
reject.Text = "Reject";
int idRequest = Convert.ToInt32(dr["IDRequest"]);
userName.Text = CultureInfo.CurrentCulture.TextInfo.ToTitleCase(dr["UserFirstName"].ToString() + " " + dr["UserLastName"].ToString());
userName.Tag = idRequest;
accept.Tag = idRequest;
reject.Tag = idRequest;
accept.Click += Accept_Click;
reject.Click += Reject_Click;
friendRequestPanel.Controls.Add(userName);
friendRequestPanel.Controls.Add(accept);
friendRequestPanel.Controls.Add(reject);
}
}
}
}
}
Requests.Start();
}
private void Reject_Click(object sender, EventArgs e)
{
Button c = sender as Button;
int idRequest = Convert.ToInt32(c.Tag);
var ctrls = friendRequestPanel.Controls
.Cast<Control>()
.Where(x =>
Convert.ToInt32(x.Tag) == idRequest);
foreach (Control ct in ctrls)
{
friendRequestPanel.Controls.Remove(ct);
ct.Dispose();
}
updateFriendRequestDatabase(2);
}
private void Accept_Click(object sender, EventArgs e)
{
Button c = sender as Button;
int idRequest = Convert.ToInt32(c.Tag);
var ctrls = friendRequestPanel.Controls
.Cast<Control>()
.Where(x => x.Tag != null &&
Convert.ToInt32(x.Tag) == idRequest);
foreach (Control ct in ctrls)
{
friendRequestPanel.Controls.Remove(ct);
ct.Dispose();
}
updateFriendRequestDatabase(1);
}
图片:GUI
当任一按钮被点击:GUI
为什么没有删除 '接受' 按钮?
你其实放置断点在代码和台阶的贯通,看看那里的预期失败..请做到这一点首先你可以不要期望我们根据您发布的所有代码对您进行代码审查。谢谢 – MethodMan
“这是我的代码,修复它” – LaneL
同意。我问自己的第一个问题是,“OP是否调试了他自己的代码?”您在ctrls枚举中接受按钮? – Amy