匿名类型属性的别名

创建匿名类型以便为属性名称创建别名时可以吗？匿名类型属性的别名

我的问题是，我的属性名称是相当大的，我试图JSON数据保持在最低限度，以使其更加轻便，而不是改变，这是非常描述实际的属性名称，我是想知道我是否可以为每个属性创建一个别名？

var result = myModel.Options.Select(l => new { l.Id, l.LargePropertyName, l.LargePropertyName2 }).ToDictionary(l => l.Id.ToString(), l => new { l.LargePropertyName1, l.LargePropertyName2 }); 
JavaScriptSerializer serializer = new JavaScriptSerializer(); 
Json = serializer.Serialize(result);

非常感谢

来源

2012-02-13 Wildcat

下面的代码片段：

var resultWithLengthyPropertyNames = new { Identificator = 1, VeryLengthyPropertyName1 = "Fred", VeryLengthyPropertyName2 = "Brooks" }; 

var serializer = new System.Web.Script.Serialization.JavaScriptSerializer(); 
var sourceJSON = serializer.Serialize(resultWithLengthyPropertyNames); 

System.Console.WriteLine("Source JSON => {0}", sourceJSON); 

string[] propertyNamesAliases = { "ID", "FN", "LN"};   
var intermediateResult = (IDictionary<string, object>)serializer.DeserializeObject(sourceJSON); 
var renamedIntermediateResult = new Dictionary<string, object>(); 
for (int i = 0; i < propertyNamesAliases.Length; i++) 
    renamedIntermediateResult.Add(propertyNamesAliases[i], 
     intermediateResult[intermediateResult.Keys.ToArray()[i]]); 

var convertedJSON = serializer.Serialize(renamedIntermediateResult); 

System.Console.WriteLine("Converted JSON => {0}", convertedJSON);

结果测试输出：

Source JSON => {"Identificator":1,"VeryLengthyPropertyName1":"Fred","VeryLengthyPropertyName2":"Brooks"} 
Converted JSON => {"ID":1,"FN":"Fred","LN":"Brooks"}

解决方案没有创建重命名属性新的匿名对象名称，但它确实解决了保持JSON字符串轻量级的任务，不是吗？

P.S.这里是第二种解决方案：

var resultWithLengthyPropertyNames = new { Identificator = 1, VeryLengthyPropertyName1 = "Fred", VeryLengthyPropertyName2 = "Brooks" }; 

var serializer = new System.Web.Script.Serialization.JavaScriptSerializer(); 
var sourceJSON = serializer.Serialize(resultWithLengthyPropertyNames); 

System.Console.WriteLine("Source JSON => {0}", sourceJSON); 

Dictionary<string, string> propertyNamesAliases = new Dictionary<string, string>() 
      { 
       { "Identificator", "ID"}, 
       { "VeryLengthyPropertyName1", "FN" }, 
       { "VeryLengthyPropertyName2", "LN" } 
      }; 

var renamedTempResult = new Dictionary<string, object>(); 

foreach (PropertyDescriptor propertyDescriptor in TypeDescriptor.GetProperties(resultWithLengthyPropertyNames)) 
{ 
    renamedTempResult.Add(
      propertyNamesAliases[propertyDescriptor.Name], 
      propertyDescriptor.GetValue(resultWithLengthyPropertyNames)); 
} 

var convertedJSON = serializer.Serialize(renamedTempResult); 

System.Console.WriteLine("Converted JSON => {0}", convertedJSON);

P.P.S.这是另一种解决方案 - 似乎是通过创建具有别名属性的匿名对象直接解决任务：

var resultWithLengthyPropertyNames = new { Identificator = 1, VeryLengthyPropertyName1 = "Fred", VeryLengthyPropertyName2 = "Brooks" }; 

var serializer = new System.Web.Script.Serialization.JavaScriptSerializer(); 

var sourceJSON = serializer.Serialize(resultWithLengthyPropertyNames); 

System.Console.WriteLine("Source JSON => {0}", sourceJSON); 

var targetObjectTemplate = new { ID = -1, FN = "", LN = "" }; 

var convertedObject = 
      Activator.CreateInstance(targetObjectTemplate.GetType(), 
        resultWithLengthyPropertyNames.GetType() 
       .GetProperties() 
       .Select(p => p.GetValue(resultWithLengthyPropertyNames)) 
       .ToArray()); 

var convertedJSON = serializer.Serialize(convertedObject); 

System.Console.WriteLine("Converted JSON => {0}", convertedJSON);

来源

2013-03-15 11:03:15 ShamilS

匿名类型属性的别名

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