0
def Skew(Text):
skew = {}
n = len(Text)
skew[0] = 0
for i in range(1,n+1):
#Every time we encounter a G, skew[i] is equal to skew[i-1]+1
if Text[i-1] == "G": skew[i] = skew[i-1]+1
#every time we encounter a C, Skew[i] is equal to Skew[i-1]-1
elif Text[i-1] == "C": skew[i] = skew[i-1]-1
#otherwise, Skew[i] is equal to Skew[i-1]
else: skew[i] = skew[i-1]
return skew
Text = "CCGGCCGG"
positions = [] #output variable
skew = Skew(Text)
print skew
minimum = min(skew.values())
print minimum
#use the for loop, to look for i when Skew[i]=minimum
for i in skew:
if skew[i] == minimum: positions.append(i)
positions = positions[1:]
print positions
“”“这是我的代码(道歉,第一次使用),但它不会做我想做的。如果你运行代码,最小值为 - 2,有2个按键与-2所以位置应该有两个结果,而不是一个。有人可以解释为什么这种情况持续发生?“””分函数只打印一个结果,而不是两个
那是因为你用这一行删除第一个结果:positions = positions [1:]。 –
@PiotrDabkowski。我现在看到了。谢谢 – FunmitoA