Foreach循环+关联数组

Question

如果我有以下代码：

$employeeAges; 
$employeeAges["Lisa"] = "28"; 
$employeeAges["Jack"] = "16"; 
$employeeAges["Ryan"] = "35"; 
$employeeAges["Rachel"] = "46"; 
$employeeAges["Grace"] = "34"; 

foreach($employeeAges as $name => $age){ 
    echo "Name: $name, Age: $age <br />"; 
} 

我怎么能输出的具体信息？下面是一个错误的书面例子：

foreach($employeeAges as $name => $age) { 
    $selective = $name["Lisa"]->$age; 
    $secondary = $name["Grace"]->$age; 
    echo "The person you're looking for is $selective years old. And the other one is $secondary years old."; 
} 

正如你所看到的，我想只抓住特定$ key的$值。上面的代码输出以下错误：

Trying to get property of non-object 

有人可以帮助这段代码？不胜感激。

Answer 1

如果我理解你的权利，你只是想获得一个特定的人的年龄，只是这样做：

$selective = $employeeAges["Lisa"]; 
$secondary = $employeeAges["Grace"]; 
echo "The person you're looking for is $selective years old. And the other one is $secondary years old."; 

的->运算符是用于访问对象的命名成员。请参阅：http://www.php.net/manual/en/language.oop5.basic.php

正如在评论中讨论，通过数组迭代找到一个特定的键，这样做：

foreach ($employeeAges as $name => $age) { 
    if ($name == "Grace") { 
     echo $name . " is " . $age . " years old"; 
     break; 
    } 
} 

Answer 2

所以你要打印出来只年龄？

$employeeAges; 
$employeeAges["Lisa"] = "28"; 
$employeeAges["Jack"] = "16"; 
$employeeAges["Ryan"] = "35"; 
$employeeAges["Rachel"] = "46"; 

$ employeeAges [“Grace”] =“34”;

foreach($employeeAges as $name=>$age) { 
    echo $age; 
} 

使用像这样的foreach循环只是强迫键进入$name和价值为$age，而不必在对象上调用，因此你的错误。

我认为@jli有一个更好的答案适合您的问题，但。

Answer 3

我有不同的解释

<?php 
//Assuming this is your array 

$employeeAges["Lisa"] = "28"; 
$employeeAges["Jack"] = "16"; 
$employeeAges["Ryan"] = "35"; 
$employeeAges["Rachel"] = "46"; 
$employeeAges["Grace"] = "34"; 

echo $employeeAges["Lisa"]; //Will output 28 
echo $employeeAges["Jack"]; //Will output 16 
echo $employeeAges["Grace"]; //Will output 34 

你只需要指定你想要的关键问题，它将输出值。