我正在试图创建一个从随机抽取卡片的程序。问题是我需要使抽签过程实际上是随机的,因为当没有其他因素改变时使用srand和rand时每个抽签是相同的。因此我将它附加到time_t秒,并且能够使绘制半/随机。这是因为我必须等待一秒钟才能改变time_t秒的参数。这是一个问题的原因是,如果我的程序绘制同一张牌两次(这是众所周知的),我的程序再次绘制。因此,如果它确实画两次相同的牌,它将被强制抽出约15次(或更多或更少),直到time_t秒参数改变。有没有办法测量毫秒或其他更小的时间单位,所以我没有这个问题?C++时间和随机函数
下面是代码,虽然对于比赛和组织proceedures检查不连接(仅那些最初的平局之后发生反正。)
int allow = 0;
string cards[] =
{"02hearts", "03hearts", "04hearts", "05hearts", "06hearts", "07hearts", "08hearts","09hearts", "10hearts", "11hearts", "12hearts", "13hearts", "14hearts",
"02clubs", "03clubs", "04clubs", "05clubs", "06clubs", "07clubs", "08clubs", "09clubs", "10clubs", "11clubs", "12clubs","13clubs", "14clubs","14clubs",
"02spades", "03spades", "04spades", "05spades", "06spades", "07spades", "08spades", "09spades", "10spades", "11spades", "12spades", "13spades", "14spades",
"02diamonds", "03diamonds", "04diamonds", "05diamonds", "06diamonds", "07diamonds", "08diamonds", "09diamonds", "10diamonds", "11diamonds", "12diamonds", "13diamonds", "14diamonds"};
string cardHand [5];
string cardnumbers [5];
int cardInts [5];
string handSuites [5];
char handSuitesChar [5];
//check deck
while(allow == 0)
{
//set clock
time_t seconds;
time(&seconds);
srand((unsigned int) seconds);
int type;
//initiate counters
int n = 0;
int n1 = 0;
int n2 = 0;
int n3 = 0;
int n4 = 0;
//draw cards
while(n < 5)
{
type = rand() % 52;
cardHand[n] = cards[type];
cout << cardHand[n] << ", ";
n++;
}
cout << endl;
//pull numbers from cards
while(n1 < 5)
{
string character2;
cardnumbers[n1] = cardHand[n1].at(0);
character2 = cardHand[n1].at(1);
cardnumbers[n1].append(character2);
cout << cardnumbers[n1] << ", ";
n1++;
}
cout << endl;
cout << endl;
//convert numbers to ints
while(n2 < 5)
{
stringstream convert(cardnumbers[n2]);
if(!(convert >> cardInts[n2]))
cardInts[n2] = 0;
cout << cardInts[n2] + 100 << ", ";
n2++;
}
cout << endl;
//pull out first letters for suites
while (n3 < 5)
{
handSuites[n3] = cardHand[n3].at(2);
cout << handSuites[n3]<< endl;
n3++;
}
//convert letters to chars
while (n4 < 5)
{
stringstream convert(handSuites[n4]);
if(!(convert >> handSuitesChar[n4]))
handSuitesChar[n4] = 0;
cout << handSuitesChar[n4] + 100 << ", ";
n4++;
}
不要随意绘制它们。随机洗牌并依次绘制。参见[这个例子](http://en.cppreference.com/w/cpp/algorithm/random_shuffle)使用'std :: random_shuffle'。 –