所以这是我的代码下面的登录菜单,一旦用户登录我想登录菜单被隐藏或删除,我试过.withdraw()和.destroy(),即时通讯确定即时通讯将代码放入错误的地方,任何援助将不胜感激!如何打开顶层时删除登录窗口?
from tkinter import *
import tkinter as tk
import sqlite3
import hashlib
import os
import weakref
def main():
root = Tk()
width = 600 #sets the width of the window
height = 600 #sets the height of the window
widthScreen = root.winfo_screenwidth() #gets the width of the screen
heightScreen = root.winfo_screenheight() #gets the height of the screen
x = (widthScreen/2) - (width/2) #finds the center value of x
y = (heightScreen/2) - (height/2) #finds the center value of y
root.geometry('%dx%d+%d+%d' % (width, height, x, y))#places screen in center
root.resizable(width=False, height=False)#Ensures that the window size cannot be changed
filename = PhotoImage(file = 'Login.gif') #gets the image from directory
background_label = Label(image=filename) #makes the image
background_label.place(x=0, y=0, relwidth=1, relheight=1)#palces the image
logins = login(root)
root.mainloop()
class login(Tk):
def __init__(self, master):
self.__username = StringVar()
self.__password = StringVar()
self.__error = StringVar()
self.master = master
self.master.title('Login')
userNameLabel = Label(self.master, text='UserID: ', bg=None, width=10).place(relx=0.300,rely=0.575)
userNameEntry = Entry(self.master, textvariable=self.__username, width=25).place(relx=0.460,rely=0.575)
userPasswordLabel = Label(self.master, text='Password: ', bg=None, width=10).place(relx=0.300,rely=0.625)
userPasswordEntry = Entry(self.master, textvariable=self.__password, show='*', width=25).place(relx=0.460,rely=0.625)
errorLabel = Label(self.master, textvariable=self.__error, bg=None, fg='red', width=35).place(relx=0.508,rely=0.545, anchor=CENTER)
loginButton = Button(self.master, text='Login', command=self.login_user, bg='white', width=15).place(relx=0.300,rely=0.675)
clearButton = Button(self.master, text='Clear', command=self.clear_entry, bg='white', width=15).place(relx=0.525,rely=0.675)
self.master.bind('<Return>', lambda event: self.login_user()) #triggers the login subroutine if the enter key is pressed
def login_user(self):
username = self.__username.get()
password = self.__password.get()
hashPassword = (password.encode('utf-8'))
newPass = hashlib.sha256()
newPass.update(hashPassword)
if username == '':
self.__error.set('Error! No user ID entered')
elif password == '':
self.__error.set('Error! No password entered')
else:
with sqlite3.connect ('pkdata.db') as db:
cursor = db.cursor()
cursor.execute("select userID, password from users where userID=?",(username,))
info = cursor.fetchone()
if info is None:
self.__error.set('Error! Login details not found!')
else:
dbUsername = info[0]
dbPassword = info[1]
if username == dbUsername or newPass.hexdigest() == dbPassword:
self.open_main_menu()
self.master.withdraw()
else:
self.__error.set('Error! please try again')
self.clear_entry()
def destroy(self):
self.master.destroy()
def clear_entry(self):
self.__username.set('')
self.__password.set('')
def open_main_menu(self):
root_main = Toplevel(self.master)
root_main.state('zoomed')
Main = main_menu(root_main)
root_main.mainloop()
class main_menu():
def __init__(self, master):
pass
if __name__ == '__main__':
main()
1:你有两个主循环,当你只应该最多只能有一个。 2:登录不应该是Tk的子类,因为它将使登录成为“根” – abccd
Naseem,我从您的个人资料中看到,您已经获得了几个问题的答案,但是您没有接受或投票支持任何一个问题。我建议阅读[我应该怎么做当有人回答我的问题?](http://stackoverflow.com/help/someone-answers) –
我可以upvote一个答案,但我有更少的15代表因此不公开。会赞成那些有帮助的人。感谢Nas –