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我需要补360元矩阵与不同phiStart和phiExit值90个元素周期:我怎样才能简化这个循环?
flute = 4;
phiStart = 0;
phiExit = 90;
phiDelta = 1;
phiPitch = 360/flute;
for g = 0:abs(phiExit - phiStart);
for k = 0:abs(phiExit - phiStart);
for j = 0:abs(phiExit - phiStart);
for m = 0:abs(phiExit - phiStart);
for i = 0:abs(phiExit - phiStart);
answerA = phiStart + i * phiDelta;
phi(i+1) = answerA;
end
answerA = phiStart + m * phiDelta;
phi(m + phiPitch) = answerA;
end
answerA = phiStart + j * phiDelta;
phi(j + 2 * phiPitch) = answerA;
end
answerA = phiStart + k * phiDelta;
phi(k + 3 * phiPitch) = answerA;
end
answerA = phiStart + g * phiDelta;
phi(g + 4 * phiPitch) = answerA;
end
b = (phi > 0); % dummy matrix for edge cofficients
h = feedRate * sin(phi/180 * pi);
这是什么语言? (Matlab?) – ysap
'phiStart'和'phiDelta'是常量。为什么你需要嵌套循环?是否有任何'phi'值被一次又一次覆盖? – ysap
是phiStart和phiExit是我定义的常量。我需要填写这样的矩阵。可以说有15个成员的行矩阵。 phiStart = 2 phiExit = 4并且周期是5 ----->因此,矩阵应该是[2 3 4 0 0 2 3 4 0 0 2 3 4 0 0]我需要用最简单的方法求解矩阵360个成员该语言是matlab。感谢您的帮助 –